Water molecules stick to nearby water molecules due to

Suppose water did not form hydrogen bonds.

Vilka [71]

-70°C

Sink

little

hydrogen bonding

Explanation:

Completing the statements:

Water's boiling point would have been close to -70°C. Ice would sink in water. Water would release little heat to warm land during the winter. Ice is less dense than water because of the hydrogen bonding that forms a hexagonal structure in water.

The unique property of water is as a result of its hydrogen bonding. Water is a polar covalent compound. Like most covalent compound, water would have naturally had a very low boiling point.

The intermolecular forces all hydrogen bonding gives water its unique nature.

Hydrogen bond is formed by an attraction between hydrogen one water water molecule and more electronegative atom on another molecule usually oxygen, nitrogen and fluorine.

They form very strong intermolecular interaction responsible for the behavior of water.

The higher specific heat capacity of water is due to this bond. It absorbs a lot of heat and does not release them on time. This causes water release heat during winter.

Water has a hexagonal shape or structure linking each molecules.

learn more;

Hydrogen bonding brainly.com/question/10602513

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5 0

2 years ago

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An object was measured by a worker as

marusya05 [52]

<h2>Answer - 0.73%</h2>

14.6 .2

=

100 x

(Above is proportions I used to get the answer)

x = 0.73% which is the answer.

6 0

2 years ago

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Measure the initial temperature of the water to the

LuckyWell [14K]

Answer:

Answer:

100

22.4

27.1

Explanation:

Explanation:

just did it on edge .

Hope this helps

8 0

2 years ago

How many moles of S would I have if I had 11 grams? (Stoichiometry) HELP

zepelin [54]

<h3>Answer:</h3>

0.34 mol S

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

11 g S

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of S - 32.07 g/mol

<u>Step 3: Convert</u>

Set up: $\displaystyle 11 \ g \ S(\frac{1 \ mol \ S}{32.07 \ g \ S})$
Multiply/Divide: $\displaystyle 0.343 \ mol \ S$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

0.343 mol S ≈ 0.34 mol S

4 0

2 years ago

A hypothetical covalent molecule, X–Y, has a dipole moment of 1.93 1.93 D and a bond length of 109 pm. 109 pm. Calculate the par

Gnesinka [82]

Answer:

q= 110.5 ke

Explanation:

Dipole moment is the product of the separation of the ends of a dipole and the magnitude of the charges.

μ = q * d

μ= Dipole moment (1.93 D)

q= partial charge on each pole

d= separation between the poles(109 pm).

e= electronic charge ( 1.60217662 × 10⁻¹⁹ coulombs)

So,

q= $\frac{1.93}{109 * 10^{-12} }$ coulombs

q = $\frac{1.93}{109 * 10^{-12} * 1.60217662 * 10^{-19} }$ e

q = 1.105 * 10⁵ e

q= 110.5 ke

4 0

2 years ago