Answer:
The structure for the compound elucidated (4-Ethylbenzoic acid) is attached below.
Explanation:
Degree of Unsaturation = 
(where n = no of moles)
= 
= 9 - 6+1 = 4
⇒ 2 ring. 3 double bonds.
From the 1H NMR data given (peaks labeled A-E)
A. 1.2 (3H, t) ⇒ -CH3
B. 2.6 (2H, q) ⇒ -C=C-H or Aromatic-CH3
C. 7.3 (2H, d) ⇒ Aro.-H
D. 8.0 (2H, d) ⇒ Aro.-H
E. 11.0 (1H, s) ⇒ -COOH
Answer:
1. 67.2 kJ/mol
Explanation:
Using the derived expression from Arrhenius Equation
Given that:
time 
= 8.3 days = (8.3 × 24 ) hours = 199.2 hours
time 
= 10.6 hours
Temperature 
= 0° C = (0+273 )K = 273 K
Temperature 
= 30° C = (30+ 273) = 303 K
Rate = 8.314 J / mol
Since 
Then we can rewrite the above expression as:
I believe that it is 187.56 g/mol
The most suitable answer is C becuase they would gain two elctrons to atain that stable OCTET thus becoming a anion with a charge of -2 and by virtue oxidation states of -2. There is however an exception with oxygen in two cases. But I still remain that the best answer would be C
