Answer:
Tread design on car B would yield a larger coefficient of static friction between the tires and the road
Explanation:
The car model using the coefficient of static friction doesn't work well with tires. A higher coefficient of static friction would require more force to cause a loss of attraction.
The static frictional force helps to keep the unbanked horizontal turn. This means that the frictional force is the centripetal force.
The tread design of car B ensures that the centripetal force is enough to negotiate the turn. On the other hand, the tread design of car A does not provide the necessary centripetal force, hence car A is unable to negotiate the turn.
Therefore, tread design on car B would yield a larger coefficient of static friction between the tires and the road.
Reactivity is the ability of matter that allows it to easily chemically combine with other substances.
Answer:
I₂ = 25.4 W
Explanation:
Polarization problems can be solved with the malus law
I = I₀ cos² θ
Let's apply this formula to find the intendant intensity (Gone)
Second and third polarizer, at an angle between them is
θ₂ = 68.0-22.2 = 45.8º
I = I₂ cos² θ₂
I₂ = I / cos₂ θ₂
I₂ = 75.5 / cos² 45.8
I₂ = 155.3 W
We repeat for First and second polarizer
I₂ = I₁ cos² θ₁
I₁ = I₂ / cos² θ₁
I₁ = 155.3 / cos² 22.2
I₁ = 181.2 W
Now we analyze the first polarizer with the incident light is not polarized only half of the light for the first polarized
I₁ = I₀ / 2
I₀ = 2 I₁
I₀ = 2 181.2
I₀ = 362.4 W
Now we remove the second polarizer the intensity that reaches the third polarizer is
I₁ = 181.2 W
The intensity at the exit is
I₂ = I₁ cos² θ₂
I₂ = 181.2 cos² 68.0
I₂ = 25.4 W
Answer:
230.4kg
Explanation:
volume of the room = l× b×h
volume= 8×6×4
volume=192m3
density= mass/volume
hence mass= density × volume
mass= 1.2kgm-3 × 192m3
mass= 230.4kg
White light is light that's made up of ALL colors.
If you have a source of white light and you want red light,
then you have to REMOVE all the other colors from the
white light somehow.
That's what a red filter does. The dye in the filter has chemicals
that absorb every color of light except red. Then, red light is the
only thing left to come out of the other side.
(If the light going into the filter had no red in it, then the filter
would appear black, because there wouldn't be any light
coming out of it at all.)
