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eduard
2 years ago
6

Where must an object be placed to form an image 30.0 cm from a diverging lens with a focal length of 43.0 cm?

Physics
1 answer:
Schach [20]2 years ago
6 0
Using lens equation;

1/o + 1/i = 1/f; where o = Object distance, i = image distance (normally negative), f = focal length (normally negative)

Substituting;

1/o + 1/-30 = 1/-43 => 1/o = -1/43 + 1/30 = 0.01 => o = 1/0.01 = 99.23 cm

Therefore, the object should be place 99.23 cm from the lens.
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