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eduard
3 years ago
6

Where must an object be placed to form an image 30.0 cm from a diverging lens with a focal length of 43.0 cm?

Physics
1 answer:
Schach [20]3 years ago
6 0
Using lens equation;

1/o + 1/i = 1/f; where o = Object distance, i = image distance (normally negative), f = focal length (normally negative)

Substituting;

1/o + 1/-30 = 1/-43 => 1/o = -1/43 + 1/30 = 0.01 => o = 1/0.01 = 99.23 cm

Therefore, the object should be place 99.23 cm from the lens.
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Forces and pres
Sliva [168]

Answer:

A.  It is zero.

Explanation:

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2 years ago
A car traveling at 60 mph has how much more energy than a car going at 15 mph?
VikaD [51]

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No, if a car is going faster. The RPM is obviously higher. If that is higher, you can burn through gas and energy much faster. A car going at 15mph would be cruising and wouldn't have to worry too much about burning our your vehicle.

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3 years ago
What connects the upper motor neurons to lower motor neurons?
skad [1K]

Answer:

The upper motor neurons synapse in the spinal cord connect with anterior horn cells of lower motor neurons, usually via interneurons. The anterior horn cells are the cell bodies of the lower motor neurons and are located in the grey matter of the spinal cord.

Explanation:

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7 0
3 years ago
Find the mass of an object if a 40 N of force causes the object to accelerate at 5.5 m/s/s
Murrr4er [49]

Answer:

<h3>The answer is 8 kg</h3>

Explanation:

The mass of the object can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{40}{5}  \\

We have the final answer as

<h3>8 kg</h3>

Hope this helps you

7 0
3 years ago
A hiker determines the length of a lake by listening for the echo of her shout reflected by a cliff at the far end of the lake.
ArbitrLikvidat [17]

Answer:

L = 499 m

Explanation:

  • If we assume that the speed of sound is constant, that travels along a straight line, and that the echo is instantaneous, we can find the total distance travelled by the sound, as follows, just applying the definition of average velocity:

       \Delta x = v_{s} * t = 343 m/s* 2.91 s = 998 m

  • If we assume that the time needed to reach to the cliff, is the same used for the return travel, the length of the lake will be exactly half of the total distance calculated:

        l_{lake} = \frac{\Delta x}{2} = \frac{998m}{2} = 499 m

  • The length of the lake is 499 m.
8 0
3 years ago
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