Change in size because that just means that more is added rather than anything reacting
The molarity of the aqueous acid solution : 0.0101 M
<h3>Further explanation </h3>
Titration is a procedure for determining the concentration of a solution by reacting with another solution that is known to be concentrated (usually a standard solution). Determination of the endpoint/equivalence point of the reaction can use indicators according to the appropriate pH range
Acid-base titration formula
Ma. Va. na = Mb. Vb. nb
Ma, Mb = acid base concentration
Va, Vb = acid base volume
na, nb = acid base valence (amount of H⁺, OH⁻)
Va=12.5 ml
na = 2 (H₂SO₄⇒2H⁺+SO₄²⁻⇒2 ion H⁺)
Mb=0.015
Vb=16.8 ml
nb = 1(LiOH⇒Li⁺+OH⁻⇒1 ion OH⁻)
The molarity of the acid(Ma) :
![\tt Ma\times 12.5\times 2=0.015\times 16.8\times 1\\\\Ma=\dfrac{0.015\times 16.8\times 1}{12.5\times 2}\\\\Ma=0.0101](https://tex.z-dn.net/?f=%5Ctt%20Ma%5Ctimes%2012.5%5Ctimes%202%3D0.015%5Ctimes%2016.8%5Ctimes%201%5C%5C%5C%5CMa%3D%5Cdfrac%7B0.015%5Ctimes%2016.8%5Ctimes%201%7D%7B12.5%5Ctimes%202%7D%5C%5C%5C%5CMa%3D0.0101)
The answer is work i believe
Answer:
2.34g of NaCl
Explanation:
HCl(aq) + NaOH(aq) --------> NaCl(aq) + H2O(l)
Number of moles of HCl= 8 × 5/1000= 0.04 moles
Number of moles of NaOH= 2.4 × 20/1000= 0.048 moles
HCl is the limiting reactant
From the balanced reaction equation, 1 mole of HCl produced 58.5g of NaCl
0.04 moles of HCl will produce 0.04 × 58.5 = 2.34g of NaCl
False because how is a metal gonna turn into a different kind