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3 years ago

Why do gases have fluidity

2 answers:

3 0

We regard liquid and gases as fluid because they they have very less or almost negligible force of attraction and very large intermolecular spaces and hence they can flow in any direction. Same is the reason of its fluid nature.

Vikki [24]3 years ago

3 0

Gases are considered to have fluidity as the particles of molecules in gases are loosely packed and hence have the ability to flow or move freely with ease. The substances that have the ability to flow is considered to have fluidity.

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Could you please Calculate the number of atom of 40K (potassium 40) in 1gram of KCl. Taking into account the isotopic abundance

Crank

Answer:

$9.53*10^{17}$ atoms of 40K

Explanation:

You can use the molecular mass and the Avogadro´s number, in the following formula:

$N_{40K=\frac{m_{KCl}}{M_{MKCl}}}*N_{Avogadro}*(IA_{40k})$

where $m_{KCl}$ is the sample mass, $M_{KCl}$ is the molecular mass of the KCl and IA(40K) is the isotopic abundance of 40K.

Now replacing the values, you can find:

$N_{40K}=\frac{1g}{74.5513\frac{g}{mol}}*6.022*10^{23}mol^{-1} *0.000118$

$N_{40K}=9.53*10^{17} atoms$

8 0

3 years ago

6) Which of the following does not fall in the biotic component of the ecosystem?

zlopas [31]

Answer:

6.grass

7.xylem

8.oval

9. poor growth of bones and teetn

4 0

3 years ago

From a cross between a short-haired guinea pig (hh) and a long-haired guinea pig (Hh), what would be the possible phenotypes of

OleMash [197]

Answer:

Explanation:

There will be a two long hair and two short hair

5 0

3 years ago

A certain substance X has a normal freezing point of 5.6 °C and a molal freezing point depression constant Kf-7.78 °C-kg·mol-1.

Harrizon [31]

Answer:

27.60 g urea

Explanation:

The freezing-point depression is expressed by the formula:

ΔT= Kf * m

In this case,

ΔT = 5.6 - (-0.9) = 6.5 °C

Kf = 7.78 °C kg·mol⁻¹

m is the molality of the urea solution in X (mol urea/kg of X)

First we calculate the molality:

6.5 °C = 7.78 °C kg·mol⁻¹ * m

m = 0.84 m

Now we calculate the moles of urea that were dissolved:

550 g X ⇒ 550 / 1000 = 0.550 kg X

0.84 m = mol Urea / 0.550 kg X

mol Urea = 0.46 mol

Finally we calculate the mass of urea, using its molecular weight:

0.46 mol * 60.06 g/mol = 27.60 g urea

7 0

3 years ago

You need to prepare a solution with a specific concentration of Na+Na+ ions; however, someone used the end of the stock solution

babymother [125]

Explanation:

Ionic equation

NaCl(aq) --> Na+(aq) + Cl-(aq)

Na2SO4(aq) --> 2Na+(aq) + SO4^2-(aq)

In NaCl solution, 1 mole of Na+ is dissociated in 1 liter of solution while in Na2SO4, 2 moles of Na+ is dissociated in 1 liter of solution.

Molecular weight of NA2SO4 = (23*2) + 32 + (16*4)

= 142 g/mol

Molecular weight of NaCl = 23 + 35.5

= 58.5 g/mol

Masses

% Mass of NA+ in Na2SO4 = mass of Na+/total mass of Na2SO4 * 100

= 46/142 * 100

= 32.4%

% Mass of NA+ in NaCl = mass of Na+/total mass of NaCl * 100

= 23/58.5 * 100

= 39.3%

Therefore, the % mass of Na+ in NaCl and Na2SO4 are different so it cannot be used.

7 0

3 years ago

Why do gases have fluidity​

Why do gases have fluidity