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Shkiper50 [21]
4 years ago
5

Why is it Xe????????????????

Chemistry
1 answer:
Tamiku [17]4 years ago
5 0

Answer:

Here's what I get.

Explanation:

Ba is element 56. Its electron configuration is

1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶ 5s²4d¹⁰5p⁶ 6s²

That's a lot of writing.

To lessen the work, chemists have developed the noble gas notation.

The core electrons of Ba (listed in boldface) have the same electron configuration as Xe, the noble gas found two atoms earlier in the Periodic Table.

Chemists replace the core electron configuration with the symbol of the corresponding noble gas.

The noble gas notation for Ba becomes

Ba: [Xe]6s².

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How many grams of KCl are there for in 10 moles of salt?
galben [10]

Your first step is determining how many gram of KCl are in every mole of KCl. This can be done by simply looking at K and Cl's atomic mass on the Periodic Table. You add K's atomic mass (39.1g) with Cl's atomic mass (35.45g) to determine that the mass of one mole of KCl is 74.55g. Because you have 10 moles of KCl you multiply 74.55g by 10 to reach your answer of 745.5g.

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4 years ago
Which is NOT a characteristic of a gymnosperm?
Alexandra [31]
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3 years ago
what is the molarity of a solution of sodium hydroxide if it 15.0 mL requires 25.0 ml of 0.25M HCl to reach the end point
DaniilM [7]

Answer:

0.42 M

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

HCl + NaOH —> NaCl + H₂O

From the balanced equation above,

The mole ratio of acid, HCl (nₐ) = 1

The mole ratio of base, NaOH (n₆) = 1

Finally, we shall determine the molarity of the base, NaOH. This can be obtained as follow:

Volume of acid, HCl (Vₐ) = 25 mL

Molarity of acid, HCl (Mₐ) = 0.25 M

Volume of base, NaOH (V₆) = 15 mL

Molarity of base, NaOH (M₆) =?

MₐVₐ / M₆V₆ = nₐ/n₆

0.25 × 25 / M₆ × 15 = 1

6.25 / M₆ × 15 = 1

Cross multiply

6.25 = M₆ × 15

Divide both side by 15

M₆ = 6.25 / 15

M₆ = 0.42 M

Therefore, the molarity of the base, NaOH is 0.42 M

6 0
3 years ago
Density is the ratio of a sample's mass to its volume. A bar of lead has a mass of 115.2 g. When it is submerged in 25.0 mL of w
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Answer:

$10.97 \ g/cm^3$

Explanation:

Given :

Mass of a bar of lead = 115.2 g

Initial water level $\text{in the graduated cylinder}$ = 25 mL

Final water level $\text{in the graduated cylinder}$ = 35.5 mL

Difference in the water level = 35.5 - 25

                                               = 10.5 mL

                                               = 10.5 \ cm^3

We know that when a body is submerged in water, it displaces its own volume of water.

Therefore, the volume of the lead bar = volume of the water displaced = 10.5 mL  = 10.5 \ cm^3

We know that mathematically, density is the ratio of mass of body to its volume.

Density of the lead bar is given by :

$\rho =\frac{\text{mass}}{\text{volume}}$

$\rho =\frac{\text{115.2 g}}{\text{10.5 cm}^3}$

  = $10.97 \ g/cm^3$

3 0
3 years ago
A car designer is designing a new model of a popular car. He wants to use the same engine as in the old model but improve the ne
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4 0
3 years ago
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