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DerKrebs [107]
3 years ago
11

A runner stood at the 100-meter mark on a track. When the timer started, the runner sprinted north to the 200-meter mark. It too

k the runner 25 seconds to get to the 200-meter mark. What was the average velocity of the runner while he was sprinting?
4 m/s north

4 m/s south

8 m/s north

8 m/s south
Chemistry
1 answer:
WITCHER [35]3 years ago
7 0

Answer:

4m/sec north

Explanation:

Given the runner sprinted from 100m mark to 200m mark, which means the displacement of the runner is 200-100=100m.

Now given the time taken to travel this 100 distance is 25 seconds

We know that Average velocity = \frac{displacement}{time}

Average velocity = \frac{100}{25}  = 4 m/sec.

We can observe from the above formulae that the direction of the average velocity is in the direction of the displacement which is given north.

Therefore the Average velocity of the runner is 4m/sec north

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What nuclide undergoes fission to form molybdenum-103, atomic number 42, tin-131, atomic number 50, and two neutrons?
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Answer:

The correct answer is Pu, 234.

Explanation:

In the given case, let us consider the reactant as X. Now the mass number (balanced) on both the sides will be,

Mass of X = Mass of Molybdenum + Mass of Tin + Mass of neutrons

M = 1 * 103 + 1 * 131 + 2 * 0

M = 234

Now the atomic number (balanced) on both the sides,

Atomic number of X = Atomic number of Molybdenum + Atomic number of Tin + Atomic number of neutrons

A = 1*42 + 1*50 + 2*1

A = 94

The atomic number 94 is for the element Plutonium, whose symbol is Pu. Thus, the reactant is 234-Pu.

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How can you tell if a chemical is a metallic bond?
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2 years ago
What is produced when an acid reacts with a base?
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The accepted value for the percent by mass of water in a hydrate is 36.0%. In a laboratory activity, a student determined the pe
valentina_108 [34]
The original or accepted value for the percent by mass of water in a hydrate = 36%
Percen by mass of water in the hydrate determined by the student
in the laboratory = 37.8%
So the difference between the actual and the percent by mass in water determined by student = (37.8 - 36.0)%
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So the percentage of error made by the student = (1.8/36) * 100 percent
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So the student makes an error of 5%. Option "1" is the correct option.
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