Question

A runner stood at the 100-meter mark on a track. When the timer started, the runner sprinted north to the 200-meter mark. It took the runner 25 seconds to get to the 200-meter mark. What was the average velocity of the runner while he was sprinting?
4 m/s north

4 m/s south

8 m/s north

8 m/s south

Answer 1

Answer:

4m/sec north

Explanation:

Given the runner sprinted from 100m mark to 200m mark, which means the displacement of the runner is 200-100=100m.

Now given the time taken to travel this 100 distance is 25 seconds

We know that Average velocity = $\frac{displacement}{time}$

Average velocity = $\frac{100}{25}$  = 4 m/sec.

We can observe from the above formulae that the direction of the average velocity is in the direction of the displacement which is given north.

Therefore the Average velocity of the runner is 4m/sec north