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Crazy boy [7]
3 years ago
15

Arrange the following atoms in order of increasing first ionization energy: He, Be, Se, Ne

Chemistry
1 answer:
Alex17521 [72]3 years ago
8 0

Answer:

Be (899 kj/mol) , Se (940.9 kj/mol), Ne(2081 kj/mol), He (2370 kj/mol),

Explanation:

For noble gases as they have complete octet so they require high amount of energy to remove the electron.

Trend along period:

As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.

Trend along group:

As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.

As the size of atom increases the ionization energy from top to bottom also  decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus.

You might be interested in
In the reaction MgCl2 + 2KOH → Mg(OH)2 + 2KCI, how many grams of KOH
dsp73

Answer:

The correct option is;

D. (2)(56 g)

Explanation:

MgCl₂ + 2KOH → Mg(OH)₂ + 2KCl

From the balanced chemical reaction equation, we have;

One mole of MgCl₂ reacts with  two moles of KOH to produce one mole of Mg(OH)₂ and 2 moles of KCl

Therefore, the number of moles of KOH that react with one mole of KCl = 2 moles

The mass, m, of the two moles of KOH = Number of moles of KOH × Molar mass of KOH

The molar mass of KOH = 56.1056 g/mol

∴ The mass, m, of the two moles of KOH = 2 moles × 56.1056 g/mol = 112.2112 grams

The amount in grams of KOH that react with one mole of MgCl₂ = 112.2112 grams ≈ 112 grams =  (2)(56 g).

4 0
3 years ago
A force of 5000 newtons is applied to a 1200 kg car at rest. What is its acceleration?
insens350 [35]
The formula for acceleration if rearranged based on the force equation is- force over mass. So 5000/1200=4.16

Your answer is 4 m/s squared.
4 0
3 years ago
Complete this reaction of a carboxylic acid with a strong base.
raketka [301]

Answer:

C6H5COOH + OH- —> C6H5COO- + H2O

Explanation:

C6H5COOH + OH- —> C6H5COO- + H2O

In the reaction above, C6H5COOH donate a proton(H+) to form the carboxylate ion C6H5COO-. The proton (H+) combines with the OH- to form H2O.

This can better be understood in the illustration below

C6H5COOH + NaOH —> C6H5COONa + H2O

6 0
3 years ago
Which of these substances are greenhouse gases? Check all that apply. Oxygen carbon dioxide helium methane nitrous oxide.
taurus [48]

The greenhouse gases are carbon dioxide, methane, and nitrous oxide.

The greenhouse effect has been defined as the entrapment of the sun's energy by the gases that result in the earth becoming warmer and a better place to live.

The gases present in the atmosphere that has been able to entrap the heat energy has been termed the greenhouse gases.

The greenhouse gases have been carbon dioxide, methane, and nitrous oxide.

For more information about  greenhouse gases, refer to the link:

brainly.com/question/11595872

3 0
3 years ago
1. A gas is confined in a cylinder with a movable piston at one end. When the volume of the
Sedaia [141]

Answer: 211 kPa

Explanation:

Given that,

Original pressure of gas (P1) = 125 kPa

Original volume of cylinder (V1) = 760 cm3

New pressure of gas (P2) = ?

New volume of cylinder (V2) = 450 cm3

Since pressure and volume are given while temperature is held constant, apply the formula for Boyle's law

P1V1= P2V2

125 kPa x 760 cm3= P2 x 450 cm3

95000 kPa•cm3 = 450 cm3•P2

Divide both sides by 450 cm3

95000 kPa•cm3/450 cm3 = 450 cm3•P2/450 cm3

211.1 kPa = P2

[Round the value of P2 to 3 significant numbers. Hence, P2 becomes 211 kPa]

Thus, the new pressure within the cylinder is 211 kPa

7 0
3 years ago
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