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viva [34]
2 years ago
13

Repeating many forms a crystal structure inside each of these repeated units is the ?

Chemistry
2 answers:
djyliett [7]2 years ago
7 0

Answer:

gggzbjv

Explanation:

vhbbn

nnkjj

vjhgnkj

jjjjjjj

Nuetrik [128]2 years ago
7 0

Answer:

unit cells; lattice

Explanation:

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They are made up of particles that are arranged in a repeating pattern.
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The molecule has two chiral carbons

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3 years ago
to produce 4.00 L of a 250 mM solution of sodium hydroxide, how many grams of naOH must be dissolved?
goldfiish [28.3K]
Multiply the volume in liters (4.00L) by the concentration of the solution in molar (0.250M) to calculate the number of moles of soluto that you need, then multiply the number of moles by the molar mass of sodium hydroxide (39.99 g/mol) to calculate the mass.

4.00L x 0.250 M x 39.99g / 1L = 39.99g

Basically you need one mol of NaOH (39.99g) dissolved in 4 liters of solution.

4 0
3 years ago
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A student needs to conduct a reaction that combines chemicals a and b to synthesize product ab. if we write this as a chemical e
balu736 [363]
The concept used here is the Law of Conservation of Mass. Technically, it's more specifically included in the Law of Definite Proportions. According to Dalton's atomic theory, when substances react together, they form a compound that has the same fixed ratio of the individual elements. That is the main reason why we balance, because stoichiometric coefficients are essential to obey the Law.

For the reaction a + b ⇒ ab, this is a combination reaction. For every 1 mole of a and 1 mole of b, 1 mole of product ab is formed. This is the fixed ratio we have to follow: 1:1:1. Now, the next thing to note is the limiting and excess reactant. If initially, there are 2 moles of A and 3 moles of B, the limiting reactant is A and the excess is B. Since the ratio between reactants is 1:1, 3 moles of B requires 3 moles of A. But since only 2 moles are available, reactant A is limited. In this problem, we assume that B is provided in excess. So, we just focus on the amount of the limiting reactant a.

If there are 5,000 molecules of a, we can determine the molecules of ab using the fixed ratio, 1 part a is to 1 part ab. Then, that means that 5,000 molecules of a would yield also 5,000 molecules of ab.                                                                                         
7 0
2 years ago
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