Connective tissue is one of the four different types of tissues. It consists of cells suspended in a matrix, and consist of fibres running through it. It’s main job is to connect internal tissues. They also support and protect internal organs. Examples include cartilage, blood, lymph and adipose tissue.
At chemical equilibrium, the rates<span> of the forward </span>reaction<span> and reverse </span>reactions<span> are: 18.2. a. equal to 0. c. at a ... </span>Spontaneous reactions<span>: 18.4. a. are </span>always exothermic<span>. b. </span>always take place<span> at a </span>rapid rate<span>. </span>
Molality pertains to a concentration of a mixture expressed in moles of solute per kg of solvent. Based on the given problem, the solute is the phosphoric acid with molecular weight of 97.99 g/mol. Assuming 1 g of sample, the mole of solute is equal to 0.244*(97.99) = 2.49x10-3 moles. The remaining percentage,t that is, 1-0.244 is the amount of solvent, which is equal to 0.756 g based on 1 gram assumption. Therefore, the molality is,
(0.244)*(mol/97.99 g)/(1-0.244)*(1 kg/1000 g) = 3.29 molala
Answer:
1.16L
Explanation:
First, let us generate the balanced equation for the reaction. This is illustrated below
2Mg + O2 —> 2MgO
Now let us covert 2.5g of Mg given in the question to moles. This is illustrated below:
Molar Mass of Mg = 12g/mol
Mass of Mg = 2.5g
Number of mole of Mg =?
Number of mole = Mass /Molar Mass
Number of mole of Mg = 2.5/24 = 0.104mole
From the equation,
2moles of Mg required 1mole of O2.
Therefore, 0.104mole of Mg will require = 0.104/2 = 0.052mole of O2
Now let us calculate the volume occupy by 0.052mole of O2. This is shown below.
1mole of a gas occupy 22.4L at stp
Therefore, 0.052mole of O2 will occupy = 0.052 x 22.4 = 1.16L
Therefore, 1.16L of O2 is required for the reaction
Answer: C. The specific heat of water is greater than the specific heat of metals.
The specific heat is defined as the amount required to raise the temperature of a unit mass of a substance by 1 degree Celsius.
This is expressed mathematically as
Q= mc∆T
Where Q is the energy/heat required which is measured in Joules.
m is the mass (grams)
c is the specific heat which is measured in joule/gram degree Celsius.
∆T- change in temperature
Substance which has a high specific heat require a lot of heat for its temperature to be raised by one degree. On the other hand substances with lower specific heat require only little amount of heat for its temperature to be raised by one degree.
Consider an equal mass of metal and water. If both are heated at the same time,the metal would become hotter than the water much faster. This is because the specific heat of the metal is lower than the water. Hence it requires only a little heat for its temperature to raised by one degree.
Thus we can conclude that the specific heat of water is much greater than that of a metal.
