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umka21 [38]
3 years ago
15

How much calcium hypochlorite (65% strength) is needed to make 200 L of 2% hypochlorite solution? (Assume that a 1% solution is

equivalent to 10,000 mg/L concentration)
Chemistry
1 answer:
g100num [7]3 years ago
5 0

To solve this we use the equation,

 

M1V1 = M2V2

 

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

 

65 x V1 = 2 x 200 L

V1 = 6.15 L

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