Question

A 22.0 nF capacitor is connected across an AC generator that produces a peak voltage of 5.80 V. part a

Answer 1

Answer:

Explanation:

Impedence of the circuit = peak voltage / peak current

= 5.8 / 51 x 10⁻³

= 113.725 ohm.

1 / wC =113.725

w = 1 / (113.725 x 22 x 10⁻⁹ )

= 10⁹ / 2.5 x 10³

=10⁶ / 2.5

40 x 10⁴

frequency n = 40 x 10⁴ / 2 x 3.14

6.37 x 10⁴ Hz.

b ) charge on the capacitor = 1 C

V = Q / C

= Charge / capacitor

= 1 / 22 x 10⁻⁹

4.54 x 10⁷ V.