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Alchen [17]
3 years ago
5

A 22.0 nF capacitor is connected across an AC generator that produces a peak voltage of 5.80 V. part a

Physics
1 answer:
mariarad [96]3 years ago
4 0

Answer:

Explanation:

Impedence of the circuit = peak voltage / peak current

= 5.8 / 51 x 10⁻³

= 113.725 ohm.

1 / wC =113.725

w = 1 / (113.725 x 22 x 10⁻⁹ )

= 10⁹ / 2.5 x 10³

=10⁶ / 2.5

40 x 10⁴

frequency n = 40 x 10⁴ / 2 x 3.14

6.37 x 10⁴ Hz.

b ) charge on the capacitor = 1 C

V = Q / C

= Charge / capacitor

= 1 / 22 x 10⁻⁹

4.54 x 10⁷ V.

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A vehicle in for repair has a burst upper radiator tank. Technician A says thermostat that was stuck in the open position could
Morgarella [4.7K]

Answer:

Technician B

Explanation:

A thermostat being stuck in an open position allows coolant to constantly circulate through the radiator which will cause a drop in the temperature of the engine. Hence, thermostat being stuck in an open position has nothing to do with burst upper radiator.

On the other hand, a radiator cap controls the pressure within the radiator which needs to be kept constant in order prevent overheating or damage to the radiator itself.

Therefore, technician B is correct.

5 0
4 years ago
A ball with mass of 0.050 kg is dropped from a height of h1 = 1 .5 m. It collides with the floor, then bounces up to a height of
Iteru [2.4K]

Answer:

Explanation:

Impulse of reaction force of floor = change in momentum

Velocity of impact = √ 2gh₁

= √ 2 x 9.8 x 1.5 = 5.4 m /s.

velocity of rebound = √2gh₂

= √ 2x 9.8 x 1

= 4.427 m / s.

Initial momentum = .050 x 5.4 = .27 kg m/s

Final momentum = .05 x 4.427 = .22 kg.m/s

change in momentum = .27 - .22 = .05 kg m/s

Impulse = .05 kg m /s

Impulse = force x time

force = impulse / time

.05 / .015 = 3.33 N.

kinetic energy = 1/2 m v²

Initial kinetic energy = 1/2 x .05 x 5.4²

= 0.729 J

Final Kinetic Energy =1/2 x .05 x 4.427²

= 0.489 J

Change in Kinetic energy =0 .24 J

Lost kinetic energy is due to conversion of energy into sound light etc.

4 0
4 years ago
List two pieces of evidence<br> related to this picture
tatyana61 [14]

Answer:

there was a crash you can tell cause of the 2 cars the dog is curious on what happened, you can tell because the dog is looking at the cash

4 0
3 years ago
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A man stands at the midpoint between two speakers that are broadcasting an amplified static hiss uniformly in all directions. Th
LiRa [457]

Answer:

A) total intensity = 5x10^-4W/m2

B) total intensity = 5.34x10^-4W/m2

Explanation:

Detailed explanation and calculation is shown in the image below

8 0
3 years ago
The orbital period of a satellite is 2 × 106 s and its total radius is 2.5 × 1012 m. The tangential speed of the satellite, writ
LenaWriter [7]

The orbital period of the satellite[T] is given as 2*10^{6} S.

The radius of the satellite is given [R] 2.5*10^{12} m.

we are asked here to calculate the tangential speed of the satellite.

Before going to get the solution first we have understand the tangential speed.

The tangential speed of a satellite is given as the speed required to keep the satellite along the orbit. If satellite speed is less than tangential speed,there is the chance of it falling down towards earth. If it is more,then it will deviate from it orbit and can't stick to the orbit further.In a simple way  the tangential speed is the linear speed of an object in a circular path.

Now we have to calculate the tangential speed [V].

Mathematically the tangential speed [V]   written as -

                                V=\frac{2\pi R}{T}

where T is the time period of the satellite and R is the radius of the satellite.

                        V=\frac{2*3.14*10^{12} }{2*10^{6} }

                               = 7.85*10^{6} m/s

There is also another way through which we can get  the solution as explained below-

We know that the tangential speed of a satellite V=\sqrt{\frac{GM}{R^{2} } }

where G is the gravitational constant and M is the mas of central object.

But we know that g=\frac{GM}{R^{2} }

                               ⇒GM=gR^{2}  where g is the acceleration due to gravity of that central object.


Hence    V=\sqrt{\frac{gR^{2} }{R} }

               ⇒   V=\sqrt{gR}

By knowing the value of g due to that central object we can also calculate its tangential speed.

                           

 




7 0
3 years ago
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