What is stopping distance of a body at 20 m/s is decelerated at 2m/s² to rest?
1 answer:
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Explanation:
The Coulomb's law states that the magnitude of each of the electric forces between two point-at-rest charges is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them:
In this case we have an electron (-e) and a proton (e), so:
In this case, the electric force is negative, therefore, the force is repulsive and its magnitude is:
- initial velocity=u=0m/s
- Final velocity=v=4m/s
- Time=t=2.5s