Answer:
(C) T
The tension T at equilibrium will be equal to the Buoyant force.
The Buoyant force is given by:
Fb = density x acceleration due to gravity x volume displaced
The change in height doesn't affect the Buoyant force and hence the tension.
Note: The figure of question is added in the attachment
Answer:
W ’= 21.78 kg
Explanation:
The expression for weight is
W = m g
let's look for the acceleration of gravity with the universal law of gravitation
F = G m M / r2
F = m (G M / r2)
without comparing the two equations
g’= G M / r2
in that case M = 2 Mo and r = 3 ro
where mo and ro are the mass and radius of the earth
we substitute
g ’= G 2Mo / (3r₀) 2
G ’= 2/9 G Mo / r₀²
g ’= 2/9 g
the weight of the body on this planet is
W ’= m g’
W ’= m 2/9 g
let's calculate
W ’= 2/9 10 9.8
W ’= 21.78 kg
X - Xo = 0.5(Vo +V)t
Xo cancels because it is 0 (she is at rest)
17 = 0.5(0+V)3.8
17 = 1.9V
Final velocity is 8.94737 m/s
Answer:
5 is the tripoid stand
Thanks have a bangtastic day
