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Rufina [12.5K]
3 years ago
10

During which change of state would the volume of a aubstance increase the most ?

Physics
1 answer:
wel3 years ago
6 0
The answer is D. Sublimation, because it has change of state it has a volume of a substances it increase the most.
You might be interested in
What form of braking is used to bring a vehicle to a smooth stop by applying smooth,steady pressure to the brake
Sav [38]

Answer:

Controlled braking

Explanation:

CONTROLLED BRAKING occur in a situation where a person or an individual driving a vehicle releases the brake and slowly apply smooth as well as firmly pressure on the brake without the wheels been locked which is why CONTROLLED BRAKING are often used for emergency stops by drivers reason been that it helps to reduce speed when driving as fast as possible while the driver maintain the steering control of the vehicle.

Therefore the form of braking which is used to bring a vehicle to a smooth stop by applying smooth,steady pressure to the brake is called CONTROLLED BRAKING.

7 0
3 years ago
How can an electron in an atom lose energy to go from a higher energy level to a lower energy level? select one:
Romashka-Z-Leto [24]
I belive that the answer is b. 
8 0
3 years ago
What is the reason that the liquid can flow?
Sergio039 [100]

Answer:

the attraction between particles

4 0
3 years ago
Miss Piggy is exercising her vocal chords by matching the frequency f = 686 Hz of her speaker 4 m away. Where should Kermit sit
monitta

Answer:

z=\frac{2n+1}{8} for n=0,1,2,3,...,15

Where z=0 m is the position of Miss Piggy and z=4 m is the position of the speaker.

Explanation:

Assuming that Miss Piggy emits a sound wave that is in phase with the speaker, and that z=0 is the position of Miss Piggy and z=4 is the position of the speaker, we would have a superposition of two traveling sound waves. Furthermore let's assume that both waves have the same amplitude. The total resulting wave will be given by:

\psi(t,z)=A\cos(\omega t-kz)+A\cos(\omega t +kz) where \omega is the angular frequency of the traveling wave and k is the wave number defined as k=\frac{2\pi}{\lambda}. \lambda is the wavelength of both traveling waves (they have the same wavelength because they have the same frequency). \lambda=\frac{v}{f} where v is the speed of sound.

By using the trigonometric identity 2\cos(A)\cos(B)=\cos(A+B)+\cos(A-B) we can rewrite \psi (t,z) as

\psi (t,z)=2A\cos(\omega t)\cos(kz).

In order for the resulting wave to have maximum destructive interference, that is to be zero for any time t, we need to have

\cos(kz)=0

\implies kz=(2n+1)\cdot \frac{\pi}{2}\implies z=(2n+1)\frac{\pi}{2k}=(2n+1)\frac{\pi}{2}\frac{\lambda}{2\pi}=(2n+1)\cdot \frac{\lambda}{4}

\implies z=(2n+1)\cdot\frac{v}{4f}=\frac{2n+1}{8}

3 0
3 years ago
In a house, 3 bulbs of 60 watt each are lighted for 3 hours daily, 4 fans of 100 watt each are used for 8 hours daily and an ele
Virty [35]

Answer:

Total Energy consumed = 146.94 kwh

Total cost = rs 587.76

Explanation:

Given:

3 bulbs each 60 watt [for 3 hours daily]

4 fans each 100 watt [for 8 hours daily

1 electric heater of 2 kWh (2,000 watt) [for half hour daily ]

Rate = rs 4/Kwh

Find:

Total Energy consumed

Total cost

Computation:

Energy used = Power × time

3 bulbs each 60 watt [for 3 hours daily]  = 3 x 60 x 3 x 31 = 16,740 watt = 16.74 kw

4 fans each 100 watt [for 8 hours daily  = 4 x 100 x 8 x 31 = 99,200 watt = 99.2 kw

1 electric heater of 2 kWh [for half hour daily ] = 1 x 2000 x (1/2) x 31 = 31,000 watt = 31 kw

Total Energy consumed = 16.74 + 99.2 + 31

Total Energy consumed = 146.94 kwh

Total cost = 146.94 x 4

Total cost = rs 587.76

5 0
3 years ago
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