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Kipish [7]
3 years ago
7

What set of reflections would carry trapezoid ABCD onto itself? (1 point) Trapezoid ABCD is shown. A is at negative 5, 1. B is a

t negative 4, 3. C is at negative 2, 3. D is at negative 1, 1. Group of answer choices x-axis, y=x, y-axis, x-axis x-axis, y-axis, x-axis y=x, x-axis, x-axis y-axis, x-axis, y-axis, x-axis
Mathematics
1 answer:
amid [387]3 years ago
6 0

Answer:

y=x, x axis,  y=x, y axis

Step-by-step explanation:

If a point A(x, y) is reflected along the y = x line, the new coordinates would be A'(y, x)

If a point A(x, y) is reflected across the x axis, the new coordinates would be A'(x, -y)

If a point A(x, y) is reflected along the y axis, the new coordinates would be A'(-x, y)

Firstly reflect Trapezoid ABCD along the y = x line to give:

A (-5, 1) ⇒ A'(1, -5). B (-4, 3) ⇒ B'(3, -4). C (-2, 3) ⇒C'(3, -2). D (-1, 1) ⇒ D'(1, -1)

Secondly reflect along the x axis to give:

A'(1, -5)⇒ A"(1,5). B'(3, -4)⇒ B"(3,4), C'(3, -2)⇒C"(3, 2), D'(1, -1) ⇒ D"(1, 1)

Thirdly reflect along the y = x line to give:

A"(1,5) ⇒ A"'(5, 1). B"(3,4) ⇒ B"'(4, 3). C"(3, 2) ⇒ C"'(2, 3). D"(1, 1) ⇒ D"'(1, 1)

Lastly reflect along the y axis to give:

A"'(5, 1) ⇒ A""(-5, 1), B"'(4, 3) ⇒ B""(-4, 3), C"'(2, 3) ⇒ C""(-2, 3), D"'(1, 1) ⇒ D""(-1.1)

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3 years ago
The table represents a linear function. find the values of a,b, and c. Show your work.
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Answer:

The values of a , b , c are ⇒ a = 1 , b = 10 , c = 9

Step-by-step explanation:

* Lets describe the meaning of the linear function

- Linear function is represented by a line graphically

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  of the line and c is the y-intercept (the point of intersection

  between the line and the y-axis is (0 , c))

- m = change of y/change of x

- We can find m from any two points on the line

* Lets use m to find a, b and c

- Use the points (3 , 8) and (5 , 9) to find m

∵ m = (y2 - y1)/(x2 - x1)

∴ m = (9 - 8)/(5 - 3) = 1/2

- Find a by using points (a , 7) and (3 , 8) ⇒ (or (5 , 9))

∵ m = (8 - 7)/(3 - a) = 1/2

∴ 1/(3 - a) = 1/2  ⇒ by using cross multiplication

∴ 3 - a = 2 ⇒ subtract 3 from both sides

∴ -a = -1 ⇒ × -1 both sides

∴ a = 1

- Find b by using points (5 , 9) and (7 , b) ⇒ (or (3 , 8))

∵ m = (b - 9)/(7 - 5) = (b - 9)/2

∴ (b - 9)/2 = 1/2  ⇒ by using cross multiplication

∴ 2(b - 9) = 2 ⇒ open the bracket

∴ 2b - 18 = 2 ⇒ add 18 to both sides

∴ 2b = 20 ⇒ ÷ 2

∴ b = 10

- Find b by using points (5 , 9) and (c , 11) ⇒ (or (3 , 8))

∵ m = (11 - 9)/(c - 5) = 2/(c - 5)

∴ 2/(c - 5) = 1/2  ⇒ by using cross multiplication

∴ c - 5 = 4 ⇒ add 5 to both sides

∴ c = 9

* The values of a , b , c are ⇒ a = 1 , b = 10 , c = 9

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