Question

When its 75 kW (100 hp) engine is generating full power, a small, single-engine airplane with mass 700 kg gains altitude at a rate of 2.5 m/s. What fraction of the engine power is being used to make the airplane climb?

Answer 1

Answer:

Fraction of engine is 0.23

Explanation:

Given Data

m=700 kg

v=2.5 m/s

Fraction=?

Solution

Work done against gravity is given as

P=Fv

where F=mg

So

P=mgv

P=(700kg)×(9.8m/$s^{2}$)×(2.5m/s)

P=17.15 kW

To find Fraction

$\frac{17.5}{75}=0.23$