3 years ago

How is C10 H16 + 8 Cl2+ 10C + 16 HCL written

Chemistry

1 answer:

Klio2033 [76]3 years ago

5 0

Answer:

10 C-8/5 - 16 e- → 10 C0 (oxidation)

16 Cl0 + 16 e- → 16 Cl-I (reduction)

Explanation:

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Answer:

$CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$

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In this case, when solid calcium carbonate, CaCO3 (s), is decomposed by the action of thermal energy (heat), solid calcium oxide, CaO (s) and carbon dioxide gas, CO2 (g) are yielded via the following reaction:

$CaCO_3\rightarrow CaO+CO_2$

However, since calcium carbonate is solid as well as calcium oxide and carbon dioxide is given off as a gas, we write:

$CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$

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