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koban [17]
3 years ago
13

Solid calcium carbonate decomposes to produce solid calcium oxide and carbon dioxide gas. Express your answer as a chemical equa

tion. Identify all of the phases in your answer.CaCO,(s)-CaO(s) + CO2(g)
Chemistry
1 answer:
Gwar [14]3 years ago
8 0

Answer:

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

Explanation:

Hello!

In this case, when solid calcium carbonate, CaCO3 (s), is decomposed by the action of thermal energy (heat), solid calcium oxide, CaO (s) and carbon dioxide gas, CO2 (g) are yielded via the following reaction:

CaCO_3\rightarrow CaO+CO_2

However, since calcium carbonate is solid as well as calcium oxide and carbon dioxide is given off as a gas, we write:

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

Which also balanced.

Best regards!

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Is density a chemical or physical property of a substance?
pychu [463]

Answer:

A physical property is a characteristic of a substance that can be observed or measured without changing the identity of the substance. Physical properties include color, density, hardness, and melting and boiling points. A chemical property describes the ability of a substance to undergo a specific chemical change.

I hope this helps you understand! <3

8 0
3 years ago
What is the total number of electron pairs shared between the carbon atom and one of the oxygen atoms in a carbon dioxide molecu
TEA [102]
The answer is 2 pairs. The carbon atom has 4 electrons and oxygen atom has 6 electrons. The purpose of shared electron is to get 8 electrons at the outer layer. So the carbon atom needs to share 4 electrons which is 2 pairs with oxygen to be stable.
7 0
3 years ago
Paradichlorobenzene, C6H4Cl2, is a component of mothballs. A solution of 2.00 g in 22.5 g of cyclohexane boils at 82.39 ∘C. The
Rina8888 [55]

Answer:

2.79 °C/m

Explanation:

When a nonvolatile solute is dissolved in a pure solvent, the boiling point of the solvent increases. This property is called ebullioscopy. The temperature change (ΔT) can be calculated by:

ΔT = Kb*W*i

Where Kb is the ebullioscopy constant for the solvent, W is the molality and i is the van't Hoff factor.

W = m1/(M1*m2)

Where m1 is the mass of the solute (in g), M1 is the molar mass of the solute, and m2 is the mass of the solvent (in kg).

The van't Hoff factor represents the dissociation of the elements. For an organic molecule, we can approximate i = 1. Thus:

m1 = 2.00 g

M1 = 147 g/mol

m2 = 0.0225 kg

W = 2/(147*0.0225)

W = 0.6047 mol/kg

(82.39 - 80.70) = Kb*0.6047*1

0.6047Kb = 1.69

Kb = 2.79 °C/m

4 0
3 years ago
15.00 grams of Chromium react with 15.00 grams of hydrobromic acid. Calculate the theoretical yield of the reaction. At STP what
s2008m [1.1K]

Answer:

(a) 18.03 g

(b) 2.105 L

(c) 85.15 %

Step-by-step explanation:

We have the masses of two reactants, so this is a<em> limiting reactant problem.  </em>

We know that we will need a balanced equation with masses, moles, and molar masses of the compounds involved.  

<em>Step 1</em>. <em>Gather all the information</em> in one place with molar masses above the formulas and masses below them.  

M_r:        52.00   80.91       291.71

                2Cr  +  6HBr ⟶ 2CrBr₃ + 3H₂

Mass/g:  15.00    15.00  

<em>Step 2</em>. Calculate the <em>moles of each reactant</em>  

  Moles of Cr = 15.00 × 1/52.00

  Moles of Cr = 0.2885 mol Cr

Moles of HBr = 15.00 × 1/80.91

Moles of HBr = 0.1854 mol HBr ×  

<em>Step 3</em>. Identify the<em> limiting reactant</em>  

Calculate the moles of CrCl₃ we can obtain from each reactant.  

<em>From Cr</em>:

The molar ratio of CrBr₃:Cr is 2 mol CrBr₃:2 mol Cr

Moles of CrBr₃ = 0.2885 × 2/2

Moles of CrBr₃ = 0.2885 mol CrCl₃

<em>From HBr: </em>

The molar ratio of CrBr₃:HBr is 2 mol CrBr₃:6 mol HBr.

Moles of CrBr₃ = 0.1854 × 2/6

Moles of CrBr₃ = 0.061 80 mol CrBr₃

The limiting reactant is HBr because it gives the smaller amount of CrBr₃.

<em>Step 4</em>. Calculate the <em>theoretical yields</em> of CrBr₃ and H₂.

Theoretical yield of CrBr₃ = 0.061 80 × 291.71/1

Theoretical yield of CrBr₃ = 18.03 g CrCl₃

The molar ratio is 3 mol H₂:6 mol HBr

   Theoretical yield of H₂ = 0.1854 × 3/6

   Theoretical yield of H₂ = 0.092 70 mol H₂

<em>Step 5</em>. Calculate the <em>volume of H₂</em> at STP

STP is 1 bar and 0 °C.

The molar volume of a gas at STP is 22.71 L.

Volume = 0.092 70 × 22.71/1

Volume = 2.105 L

<em>Step 6</em>. Calculate the <em>percent yield </em>

       % Yield = actual yield/theoretical yield × 100 %

Actual yield = 15.35 g

       % yield = 15.35/18.03 × 100

       % yield = <em>85.15 % </em>

8 0
3 years ago
27. Which of the following molecules are chiral?(EXTRA CREDIT I. 2-Chlorobutane II. 3-Bromopentane ?. 1-Bromo-2-methylpropene IV
igor_vitrenko [27]

2-Chlorobutane, 2-Bromo-3-methylbutane are chiral .

chiral condition - a compound is said to be chiral if it is surrounded by 4 different groups

I,IV are chiral

II,III are achiral

Molecular types with non-superposable mirror images are known as chiral molecules. The existence of an asymmetric carbon atom in a molecule is the characteristic that most frequently contributes to chirality. When referring to an object that cannot be superposed on its mirror counterpart, the adjective "chiral" is generally employed.

A corkscrew, golf clubs, scissors, and other chiral items all have a "handedness." Thus, one can get scissors and golf clubs that are designed for either hand. Gloves and shoes are also sold in pairs, a right and a left.

learn more about chiral molecules here:

brainly.com/question/28095208

#SPJ4

5 0
1 year ago
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