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koban [17]
3 years ago
13

Solid calcium carbonate decomposes to produce solid calcium oxide and carbon dioxide gas. Express your answer as a chemical equa

tion. Identify all of the phases in your answer.CaCO,(s)-CaO(s) + CO2(g)
Chemistry
1 answer:
Gwar [14]3 years ago
8 0

Answer:

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

Explanation:

Hello!

In this case, when solid calcium carbonate, CaCO3 (s), is decomposed by the action of thermal energy (heat), solid calcium oxide, CaO (s) and carbon dioxide gas, CO2 (g) are yielded via the following reaction:

CaCO_3\rightarrow CaO+CO_2

However, since calcium carbonate is solid as well as calcium oxide and carbon dioxide is given off as a gas, we write:

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

Which also balanced.

Best regards!

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Why do elements have different<br> properties?
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2 years ago
A hydrocarbon contains 85.7% carbon and the remainder
Viefleur [7K]

Answer:

CH₂ ;  67.1 %

Explanation:

To determine the empirical formula we need to find what the mole ratio is in whole numbers of the atoms in the compound. To do that we will first need the atomic weights of C and H and then perform our calculation

Assume 100 grams of the compound.

# mol C = 85.7 g / 12.01 g/mol = 7.14 mol

# mol H = 14.3 g /  1.008 g/mol = 14.19 mol

The proportion is 14.9 mol H/ 7.14 mol C = 2 mol H/ 1 mol C

So the empirical formula is CH₂

For the second part we will need to first calculate the theoretical yield for the 12.03 g NaBH₄  reacted and then calculate the percent yield given the 0.295 g B₂H₆ produced.

We need to calculate the moles of  NaBH₄ ( M.W = 37.83 g/mol )

1.203 g  NaBH₄ / 37.83 g/mol =  0.0318 mol

Theoretical yield from balanced chemical equation:

0.0318 mol NaBH₄ x 1 mol B₂H₆ / mol NaBH₄ = 0.0159 mol B₂H₆

Theoretical mass yield B₂H₆ = 0.0159 mol x 27.66 g/ mol =  0.440 g

% yield = 0.295 g/ 0.440 g x 100 = 67.1 %

6 0
3 years ago
Which of the following is NOT true about a C-14 atom?
romanna [79]

Answer:

option C. it contain 6 neutrons.

Explanation:

7 0
2 years ago
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