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expeople1 [14]
3 years ago
8

There were 75 roasted turkeys at Ally's Eats. Bob's Goods had 4/5 as many roasted turkeys as Ally's Eats. If Ally's Eats had 5/6

as many roasted turkeys as Charlotte's Market what was the average number of roasted turkeys owned by each of the three shops? Please help! My teacher thinks ya girl is a genius!
Mathematics
1 answer:
Sever21 [200]3 years ago
7 0

Answer:

75 roasted turkeys.

Step-by-step explanation:

Ally's Eats had 75 roasted turkeys.

Bob's Goods had 4/5 as many roasted turkeys as Ally's Eats, hence, the number of roasted turkeys Bob's Goods had is:

4/5 * 75 = 60 roasted turkeys

Ally's Eats had 5/6 as many roasted turkeys as Charlotte's Market. In other words, Charlotte's market had 6/5 as many roasted turkeys as Ally's Eats:

6/5 * 75 = 90 roasted turkeys.

The average is given as the sum of all toasted turkeys in the three shops divided by 3. Hence:

A = (75 + 60 + 90) / 3

A = 225 / 3 = 75 roasted turkeys

The average number of roasted turkeys in the three shops is 75.

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a) Nota - Puesto que la ecuación que describe el Coste ya existe en el enunciado, entonces se entiende el verbo <em>"Expresa"</em> como <em>"Describa en sus propias palabras"</em>.

Como puede apreciarse el Coste de la línea telefónica móvil aumenta linealmente con el Tiempo de consumo por parte del usuario. En consecuencia, la función de Coste queda definida como sigue:

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El Coste total por 48 horas de consumo de la línea telefónica con internet es 82 soles.

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