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3 years ago

What occurs as a salt dissolves in pure water

2 answers:

7 0

Water<span> can </span>dissolve salt<span> because the positive part of </span>water<span>molecules attracts the negative chloride ions and the negative part of </span>water<span> molecules attracts the positive sodium ions.</span>

klemol [59]3 years ago

6 0

Salt molecule dissociates into positive sodium ion and negative chlorine ion. Positive sodium ion is attracted by the negative oxygen in the water while the negative chlorine ion is attracted to positive hydrogen in the water. The salt completely dissolves.

Hope this helps :)

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Calculate the number of moles in the following: 2.8 X 10^24 atoms of Cl2

vova2212 [387]

Answer:

<h3>The answer is 4.65 moles</h3>

Explanation:

To find the number of moles given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

N = 2.8 × 10²⁴ atoms of Cl2

So we have

$n = \frac{2.8 \times {10}^{24} }{6.02 \times {10}^{23} } \\ = 4.65116279069...$

We have the final answer as

<h3>4.65 moles</h3>

Hope this helps you

7 0

3 years ago

4 examples of Substances that sublime?

AVprozaik [17]

1. Dry Ice (solid carbon dioxide)

2. Iodine

3. Arsenic

4. Naphthalene

3 0

3 years ago

What would happen to the block if it had a density of 0.500 kg/L and was placed in the same 100.0 L tank of water?

raketka [301]

I’m not sure if there was important information in the question before this one, but the answer based on the info I have is B.

The density of water is 1kg/L. Since the density of the block is less, it will float.

6 0

3 years ago

Read 2 more answers

A mixture of 117.9 g of P and 121.8 g of O, reacts completely to form P4O6 and P4O10. Find the masses of P4O6 and P4O10

Alex17521 [72]

Answer:

Mass of P4O6=103.4

P4O10=133.48

Explanation:

Balanced reaction is:

8P +8 $O_{2}$ ⇒ $P_{4} O_{6}$ + $P_{4} O_{10}$

Both reactant completely vanishes as equivalent of bot are equal.

Moles of P= $\frac{117.9}{31}$ =3.80

Moles of $O_{2}$ = $\frac{117.9}{31}$ =3.80

No. of moles of formed product are equal and is $\frac{1}{8}$ th of mole of any of reactant.

Thus weight of $P_{4} O_{6}$ = $\frac{3.80}{8}$ ×220 ≈103.41

weight of $P_{4} O_{10}$ = $\frac{3.80}{8}$ ×284 ≈133.48

4 0

2 years ago

Calcule la molaridad de una solución acuosa de ácido sulfúrico (H₂SO₄) que se preparó al mezclar, en un recipiente aforado, 4 mo

oee [108]

Considerando la definición de molaridad, la molaridad de una solución acuosa de ácido sulfúrico (H₂SO₄) es 0.5 $\frac{moles}{litro}$ .

La molaridad es una medida de la concentración de un soluto en una disolución que se define como el número de moles de soluto que están disueltos en un determinado volumen.

La molaridad de una solución se calcula dividiendo los moles del soluto por el volumen de la solución:

$Molaridad=\frac{numero de moles de soluto}{volumen}$

La Molaridad se expresa en las unidades $\frac{moles}{litro}$ .

En este caso, sabes que una solución acuosa se preparó al mezclar 4 moles del ácido con suficiente agua hasta completar 8 litros de solución. Entonces, sabes que:

número de moles de soluto= 4 moles
volumen= 8 litros

Reemplazando en la definición de molaridad:

$Molaridad=\frac{4 moles}{8 litros}$

Resolviendo:

Molaridad= 0.5 $\frac{moles}{litro}$

Finalmente, la molaridad de una solución acuosa de ácido sulfúrico (H₂SO₄) es 0.5 $\frac{moles}{litro}$ .

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2 years ago