The pounds of alloy that contains 26% copper that would be used is 23.42 pounds.
The pounds of alloy that contains 69% copper that would be used is 29.58 pounds.
<h3>What are the linear equations that represent the question</h3>
0.26a + 0.69b = (53 x 0.5)
0.26a + 0.69b = 26.50 equation 1
a + b = 53 equation 2
Where:
- a =pounds of alloy that contains 26% copper
- b = pounds of alloy that contains 69% copper
<h3>How many pounds of each alloy should be in the third alloy?</h3>
Multiply equation 2 by 0.26
0.26a + 0.26b = 13.78 equation 3
Subtract equation 3 from equation 2
12.72 = 0.43b
b = 12.72 / 0.43
b = 29.58 pounds
a = 53 - 29.58 = 23.42 pounds
To learn more about linear functions, please check: brainly.com/question/26434260
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Answer:
6
Step-by-step explanation:
Area = length x width
Input the numbers:
Area = 78
length = 13
78 = 13 x width
width = 78 / 13
width = 6
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-Chetan K
Answer:
ll;;;;.'l/lkmo;.juinop;ij[0ik0[,k[0pj978j
Step-by-step explanation:
2x+5=47, solve algebraically to find x, the answer
Answer:
quarts
Step-by-step explanation:
Total amount of drinks = 
+ 
You would want to make the denominators the same before adding them, so I will multiply the first fraction by 2 and the second one by 3 so their denominators are 6.
+ = 
+ 
Now we can directly add them together while keeping the denominator the same.
+ = quarts
