Answer:
3.416 m/s
Explanation:
Given that:
mass of cannonball
= 72.0 kg
mass of performer
= 65.0 kg
The horizontal component of the ball initially
= 6.50 m/s
the final velocity of the combined system v = ????
By applying the linear momentum of conservation:




v = 3.416 m/s
Well i don’t know i’m just doing this so i get my stuff done
Answer:
The maximum amplitude (
) will be 7.96 V.
Explanation:
We know, for distortion free operation, the slew rate (S) of an OPAMP is written as

where '
' is the highest frequency signal.
Therefore, from the above equation we can write,
