Cold temperature can't "flow" into a warmer object, in this case, the person's hand. The heat energy of the hand gets transferred to the colder object, the ice.
Answer:
(a) 2400N
(b) Yes
Explanation:
(a) Mass (m) = 1.5kg, initial speed (v) = 4m/s, time (t) = 2.5milliseconds = 2.5/1000 = 0.0025seconds
F = mv/t = (1.5×4)/0.0025 = 6/0.0025 = 2400N
(b) The force would be different because the mass of the two hands and forearms is 3kg (2 × 1.5kg = 3kg)
<span>Planet A orbits faster than Planet B, i believe is the answer. hope that helps
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Answer:
2a.
a=1.13ms^-2
2b.
S=277m
2c.
V=27.7ms-¹
Explanation:
Initial Velocity (U)=22m/s¹
Final Velocity (V)=43m/s²
Time(t) =18.6s
a. a=V-U/t
a=43-22/18.6
a=1.129
a=1.13m/s²
2b.
S=ut+1/2 at²
s=22(10)+1/2×1.13(10)²
s= 220+0.57(10)²
s= 220+0.57(100)
s= 220+57
s=277m
2c.
V=U+AT
V=22+1.13(5)
V=22+5.65
V=22+5.7
V=27.7m/s¹
Um of momenta = 0( Since both the cars stop)
<span>Let m1 be the mass of the cadillac and m2 be the mass of the volkswagen. </span>
<span>then, v1=speed of cadillac and v2=speed of volkswagen. </span>
<span>Therefore, (m1)*(v1) + (m2)*(v2) = 0 </span>
<span>Substituting, </span>
<span>(1000*4) + (2000*v2) = 0 </span>
<span>4000 = - 2000 v2 </span>
<span>Therefore, v2= - 2 m/s. </span>