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Verizon [17]
3 years ago
5

We had an experiment that is entitled "balloon rocket" it is an experiment using the force of balloon to make the straw move. it

is about law of interaction.
Did the escaping air have to hit anything to make the balloon move??

my answer here is no, because even in space, space rockets can travel even in a vacuum.

is it correct??
Physics
1 answer:
andreev551 [17]3 years ago
3 0
Air from a balloon does not need to touch anything in order for the balloon to move. The outside forces around the balloon push down it so it contracts and air is expelled. This propulsion is what moves the balloon.
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Which human activity causes the most erosion?
Ksivusya [100]

Answer:

B

Explanation:

3 0
3 years ago
A hydraulic lift has two connected pistons with cross-sectional areas 15 cm2 and 670 cm2. It is filled with oil of density 510 k
BigorU [14]

Answer:

Explanation:

Given

Cross-sectional area of two areas is

A_1=15\ cm^2

A_2=670\ cm^2

It is filled with oil of density \rho _0=510\ kg/m^3

mass of car place on Large area M=1100\ kg

Suppose a mass of m kg is placed on smaller area

According to pascal law's intensity of pressure is same at every point on Liquid

P_1=P_2

\frac{F_1}{A_1}=\frac{F_2}{A_2}

\frac{mg}{15}=\frac{Mg}{670}

m=1100\times \frac{15}{670}

m=24.62\ kg                            

4 0
3 years ago
A person opens a door by applying a 10-N force perpendicular to it at a distance 0.90m from the hinges.
quester [9]
You faded out there before asking your question. 
Here's some info that might be of interest:

Torque = (force) x (distance from the pivot) = (10 n) x (0.9 m) = 9 newton-meters
6 0
4 years ago
A particle of mass 6.3 x 10-8kg and charge 7.1 muC is traveling due east. It enters perpendicularly a magnetic field whose magni
ASHA 777 [7]

Answer:

t=0.016s

Explanation:

we can use

\frac{v}{r}=\omega=\frac{qB}{m}=\frac{7.1*10^{-6}C*1.7T}{6.3*10^{-8}kg}=191.58s^{-1}

the time that the particle is in the magnetic field is one half oa period. Hence

t=\frac{T}{2}=\frac{\pi}{\omega}=0.016s

I hope this is useful for you

regards

8 0
3 years ago
A sports car accelerates at a constant rate from rest to a speed of 90 km/hr in 8 s. What is its acceleration?
AfilCa [17]
First convert 90km/hr to m/s.

Initiate velocity = 0m/s (car was at rest)

Final velocity is 25m/s (90km/hr converted)

25m/s - 0m/s / 8s = 3.125 m/s^s

Therefore the answer is option A (3.13m/s^2)
3 0
3 years ago
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