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Verizon [17]
3 years ago
5

We had an experiment that is entitled "balloon rocket" it is an experiment using the force of balloon to make the straw move. it

is about law of interaction.
Did the escaping air have to hit anything to make the balloon move??

my answer here is no, because even in space, space rockets can travel even in a vacuum.

is it correct??
Physics
1 answer:
andreev551 [17]3 years ago
3 0
Air from a balloon does not need to touch anything in order for the balloon to move. The outside forces around the balloon push down it so it contracts and air is expelled. This propulsion is what moves the balloon.
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A baseball pitcher throws the ball towards the batter at 90 mph. His bat connects with the ball for a line drive, after which th
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Answer:

F=-18412.9N, where the minus indicates the direction is opposite to that of the throw.

Explanation:

a)

Since MKS stands for meter-kilogram-second and we know that:

1\ hour = 3600\ seconds

1\ mile = 1600\ meters

1000g = 1kg

We can write that:

\frac{1\ hour}{3600\ seconds}=1

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These are conversion factors, equal to 1, so multiplying our results by them won't change their value, only their units.

So we have that:

90 mph=90 \frac{miles}{hour}(\frac{1\ hour}{3600\ seconds})(\frac{1600\ meters}{1\ mile})=40m/s

110 mph=110 \frac{miles}{hour}(\frac{1\ hour}{3600\ seconds})(\frac{1600\ meters}{1\ mile})=48.89m/s

145 g=145 g(\frac{1kg}{1000g})=0.145kg

b)

Newton's 2nd Law tells us that F=ma, and the definition of acceleration is a=\frac{\Delta v}{\Delta t}, so we have:

F=m\frac{\Delta v}{\Delta t}=m\frac{v_f-v_i}{t}

Taking the throw direction as the positive one, for our values we have:

F=m\frac{v_f-v_i}{t}=(0.145kg)\frac{(-48.89m/s)-(+40m/s)}{0.0007s}=-18412.9N

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