Answer:
a) F = 100.375 N
b) F = 38.252 N
Explanation:
a) she is accelerated from rest to a speed of 11 m/s in 8.0 s
We get the acceleration we use this equation,
v = u + at
where v is the final velocity - 11 m/s
u = initial velocity = 0 m/s (from rest)
t is time taken = 8 s
Since v = u + at
11 = 0 + a×8
8a = 11
a = 11/8 = 1.375
a = 1.375 m/s²
The force equation is given by:
F = ma
F is the force, m is mass = 73 kg and a is acceleration
F = 73 × 1.375 = 100.375
F = 100.375 N
(b) she lets go of the tow rope and glides to a halt in 21 s.
We get the acceleration we use this equation,
v = u + at
where v is the final velocity = 0 m/s (to a halt)
u = initial velocity = 11 m/s
t is time taken = 21 s
Since v = u + at
0 = 11 + a×21
21a = -11
a = -11/21 = -0.524
a = 0.524 m/s²
The force equation is given by:
F = ma
F is the force, m is mass = 73 kg and a is acceleration
F = 73 × 0.524 = 38.252
F = 38.252 N
