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Shkiper50 [21]
2 years ago
7

Review Conceptual Example 16 as background for this problem. The water skier there has a mass of 73 kg. Find the magnitude of th

e net force acting on the skier when (a) she is accelerated from rest to a speed of 11 m/s in 8.0 s and (b) she lets go of the tow rope and glides to a halt in 21 s.
Physics
1 answer:
Slav-nsk [51]2 years ago
6 0

Answer:

a) F = 100.375 N

b) F = 38.252 N

Explanation:

a) she is accelerated from rest to a speed of 11 m/s in 8.0 s

We get the acceleration we use this equation,

v = u + at

where v is the final velocity - 11 m/s

u = initial velocity = 0 m/s (from rest)

t is time taken = 8 s

Since v = u + at  

11 = 0 + a×8

8a = 11

a = 11/8 = 1.375

a = 1.375 m/s²

The force equation is given by:

F = ma

F is the force, m is mass = 73 kg and a is acceleration

F = 73 × 1.375 = 100.375

F = 100.375 N

(b) she lets go of the tow rope and glides to a halt in 21 s.

We get the acceleration we use this equation,

v = u + at

where v is the final velocity = 0 m/s (to a halt)

u = initial velocity = 11 m/s

t is time taken = 21 s

Since v = u + at  

0 = 11 + a×21

21a = -11

a = -11/21 = -0.524

a = 0.524 m/s²

The force equation is given by:

F = ma

F is the force, m is mass = 73 kg and a is acceleration

F = 73 × 0.524 = 38.252

F = 38.252 N

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We experience fictitious forces due to: a. Rotation of a reference frame b. Inertial reference frames c. Translational motion d.
lisabon 2012 [21]

Answer:

A.

Explanation:

A fictional force (also called force of inertia, pseudo-force, or force of d'Alembert, 5), is a force that appears when describing a movement with respect to a non-inertial reference system, and that therefore it does not correspond to a genuine force in the context of the description of the movement that Newton's laws are enunciated for inertial reference systems.

The forces of inertia are, therefore, corrective terms to the real forces, which ensure that the formalism of Newton's laws can be applied unchanged to phenomena described with respect to a non-inertial reference system. The correct answer is A.

8 0
3 years ago
5. Suppose that you wish to construct a simple ac generator having an output of 24 V maximum when rotated at 120 Hz. A uniform m
vazorg [7]

Answer:

32 turns

Explanation:

From the expression for the induced emf,

E = (N)(B)(A) w

E = emf = 24 V

N = number of turns = ?

B = magnetic field strength = 0.10 T

A = Cross sectional Area of the loop = 100 cm² = 0.01 m²

w = Angular speed = (2πf) = (2π × 120) = 754.3 rad/s

24 = N (0.1)(0.01)(754.3)

N = (24/0.7543)

N = 31.8 ≈ 32 turns.

Hope this Helps!!!

6 0
3 years ago
I am pretty sure its the last one.
CaHeK987 [17]
The answer is has no moons. Mars has two moons
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2 years ago
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Which group has the Same electron shells? A Titanium and Gold B Selenium and Tin C Calcium and Magnesium D Lithium and Boron
Anna11 [10]

im not 100 percent sure but i think its b


6 0
3 years ago
An airplane is flying in a horizontal circle at a speed of 480 km/h. If its wings are tilted 40° to the horizontal, what is the
guajiro [1.7K]

Answer:

r = 2161.9 m

Explanation:

Aerodynamic lift(L) is perpendicular to the wing, which is tilted 40 degrees to the horizontal.

Since the plane is moving in a horizontal circle, the vertical component of the lift must cancel the weight W of the airplane, but the horizontal component is the centripetal force that keeps it in a circle.

L is perpendicular to wing at angle θ with respect to horizontal

Thus,

Vertical component of lift is:

L cosθ = W = mg

Thus, m = L cosθ / g - - - - (eq1)

Horizontal component of lift is:

L sinθ = centripetal force = mv² / r - - - - (eq2)

Combining equations 1 and 2,we have;

L sinθ = (L cosθ / g)(v² / r)

L cancels out on both sides to give;

tanθ = v²/ rg

r = v² / (g tanθ)

We are given;

velocity; v = 480 km/hr = 480 x 10/36 = 133.33 m/s

r = 133.33²/[(9.8) tan(40)] = 2161.9 m

3 0
3 years ago
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