Step 1: Tell them to keep their eyes on the road.Step 2: Watch them to make sure they keep their eyes on the road.Step 3: Don't converse with them because you might risk distracting them.
It makes an awkward situation but it ensures that they'll feel so pressured to keep their eyes on the road or pull over so you can call a different ride.
(a) -1620.8 J
The initial kinetic energy of the skateboarder is:

where m is the skateboarder's mass and u his initial speed;
While the final kinetic energy is

where v is his final speed.
So the change in kinetic energy is

According to the work-energy theorem, the change in mechanical energy (kinetic+potential) of the skateboarder is equal to the work done on it:

where
is the work done by the skateboarder on himself
is the work done by friction
is the change in gravitational potential energy
Solving for
,

(b) 2.97 m
The change in potential energy of the skateboarder can be written as

where
m = 55.6 kg is the mass
g = 9.8 m/s^2 is the acceleration of gravity
is the change in vertical height of the skateboarder
Solving for
,

Where the negative sign means the skateboarder has moved downwards. Since we are interested only in the absolute value, the answer is
h = 2.97 m
Chemicals are released by the damaged tissue to bring platelets to the area to become sticky and to plug the vessels. An inflammatory response occurs which brings immune cells to fight infection and other clotting factors come to begin forming a new tissue.
Answer:
Explanation:
Kinetic energy involves motion so something that is not moving has zero kinetic energy.
Potential energy does not involve motion and is based on position in a field like gravity and magnetic.
Answer:
The ruling separation must be between 2.2 × 10⁻⁶ m and 3.3 × 10⁻⁶ m
Explanation:
Fringe spacing w = λ·D/s
Diffraction grating, d·sin(θ) = n·λ
n = Number of lines
When θ = 90°, we have, sin(θ) = sin(90°) = 1
Therefore;
d·sin(θ) = d × 1 = d = n·λ
When n = 6 lines and d = 550-nm, we have;
d = 6 × 550-nm = 3,300 nm = 3.3 microns = 3.3 × 10⁻⁶ m
Therefore, the ruling separation must be between 2.2 × 10⁻⁶ m and 3.3 × 10⁻⁶ m.