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kobusy [5.1K]
3 years ago
11

Freight trains can produce only relatively small acceleration and decelerations. (a) what is the final velocity (in m/s) of a fr

eight train that accelerates at a rate of 0.0600 m/s2 for 8.00 min, starting with an initial velocity of 5.00 m/s?
Physics
2 answers:
miss Akunina [59]3 years ago
7 0
For this problem, we use the derived equations for rectilinear motion at constant acceleration.

a = (v - v₀)/t
where
a is acceleration
v₀ and v are the initial and final velocities, respectively
x is the distance
t is the time

The solution is as follows:
a = (v - v₀)/t
0.06 m/s² = (v - 5 m/s)/(8 min * 60 s/1 min)
Solving for v,
v = 33.8 m/s

m_a_m_a [10]3 years ago
5 0
(a) We will use the equation v = u + at
Initial velocity u = 5.00 m/s 
Acceleration a = 0.0600 m/s² 
time = 8 min = 8 x 60 = 480 s 
Final velocity 
= u + at 
= 5.00 + 0.0600(480) 
= 33.8 m/s

The final velocity is 33.8 m/s
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I need some help on these problems:
SCORPION-xisa [38]
Q1. The answer is 54.629 metric tons

A mass (m) of a liquid is its density (D) multiplied by its volume (V): m = D · V
Step 1. Calculate the volume (V) of the swimming pool.
Step 2. Calculate the mass (m) of the water.
Step 3. Convert the mass into the metric tones.

Step 1. 
V = w * l * h             (w - weight, l - length, h - height)
w = 3.5 m
l = 9 m
h = 1.75 m
_______
V = 3.5 * 9 * 1.75
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Step 2:
m = D * V
D = 0.991 g/cm³
1 g = 0.001 kg
1 cm³ = 0.000001 m³
D = 0.991g / 1cm³ = 0.991 * 0.001 kg / 0.000001 m³ = 991 kg/m³
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_________
m = 991 * 55.125
m = 54628.875 kg ≈ 54629 kg

Step 3.
Since 1 metric ton is 1000 kg, how many metric tons are 54629 kg?
1 mt : 1000 kg = x : 54629 kg
x = 1 mt : 1000 kg * 54629 kg
x = 54.629 metric tons



Q2. The answer is 3.2 l.
<span>
Step 1. Convert g/cm</span>³ into kg/dm³ (because 1 l = 1 dm³)
Step 2. Calculate how many liters of the liquid have a mass of 3.75 kg using the proportion

Step 1.
D = <span>1.17 g/cm3
</span>1 g = 0.001 kg
1 cm³ = 0.001 dm³
D = 1.17 * 0.001 kg / 0.001 dm³ = 1.17 kg/dm³

Step 2.
If 1.17 kg is in 1 dm³, 3.75 kg are in how many dm³:
1.17 kg : 1 dm³ = 3.75 kg : x
x =  3.75 kg * 1 dm³ : 1.17 kg
x = 3.2 dm³
1 dm³ = 1 l
x = 3.2 l



Q3. The answer is 2757140 g/m³

Step 1. Calculate the increased volume and convert units into liters.
Step 2. Calculate the density of the alloy sample and convert units into g/m³

Step 1.
The difference in the volume of the water in cylinder is:
V = 19.5 ml - 16 ml = 3.5 ml
1 ml = 0.001 l
V = 3.5 * 0.001 l = 0.0035 l

Step 2. 
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D = m/V

We have:
D = ?
m = 9.65 g
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D = 9.65/0.0035 g/l = 2757.14 g/l
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D = 2757.14 g/0.001 m³ = 2757140 g/m³
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The acceleration of the skateboard is -0.6 m/s^2 (to the left)

Explanation:

The motion of the skateboard is a uniformly accelerated motion, so we can use the following suvat equation:

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u = +8 m/s is the initial velocity

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t = 5 s is the time

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