P(<100) = P((new or change) & <100) = P(new & <100) + P(change & <100)
... = P(<100 | new)*P(new) + P(<100 | change)*P(change)
... = 0.90*0.70 + 0.20*0.30
... = 0.63 + 0.06 = 0.69 . . . . probability of completing a transaction in < 100 ms
Answer:
I'm fairly certain that c=10. Don't quote me on that.
Step-by-step explanation:
So 10% of 12=1.2 divided by
2 to get 5% which is 0.6 so because it’s increasing the amount you do $12 + 0.6 =
$12.6 if you pay online
Answer:
A the table display qualitative data, C two teachers do not wear glasses, E a total of 6 teachers were polled
