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SOVA2 [1]
3 years ago
13

Help Help Help!!! :) solve the system of equations y=2x^2-3 y=3x-1

Mathematics
1 answer:
stellarik [79]3 years ago
4 0
Solution:  
y = 2x^2 - 3 ---- equation 1
 y = 3x - 1 ------equation 2 
 Then we get, 
 2x^2 - 3 = 3x - 1 
 Now, simplifying the equation, we get 
 2x^2 - 3x - 3 + 1 = 0
 2x^2 - 3x - 2 = 0 
 After factoring the equation, we get
 (2x+1)(x-2) = 0 
 So, this means
 (2x+1) = 0 and (x-2) = 0 
 From this, we get 
 x = -1/2 and x = 2 
 Putting values of x = -1/2 in equation 2 
 y = 3(-1/2) - 1
 y = -2.5 
 Now, putting value of x = 2 in equation 2 
 y = 3(2) -1
 y = 5
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r-ruslan [8.4K]

Answer:

$1.25

September

$30

Step-by-step explanation:

Let's take this a step a time.

First we need to find how much the price of the flowers were in September.

We know that each flower cost $1.50 on October.

The October price was a 20% increase of the September price.

To calculate for the price of the flowers on September, we can solve it like this:

Let x = Price during September

1.2x = 1.50

We used 1.2 because the price of $1.50 is 120% of the original price.

Now we divide both sides by 1.2 to find x.

\dfrac{1.2x}{1.2}=\dfrac{1.5}{1.2}

x = 1.25

The price of the flowers during September was $1.25 each.

Now the 7th grade class earned 40% of the selling price of each flower.

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To find how much they made on each month, we simply multiply the percentage to the price and the number of flowers sold.

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Now for October.

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The 7th Graders earned more on September.

They earned $30 more on September than October.

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3 years ago
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