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SOVA2 [1]
4 years ago
13

Help Help Help!!! :) solve the system of equations y=2x^2-3 y=3x-1

Mathematics
1 answer:
stellarik [79]4 years ago
4 0
Solution:  
y = 2x^2 - 3 ---- equation 1
 y = 3x - 1 ------equation 2 
 Then we get, 
 2x^2 - 3 = 3x - 1 
 Now, simplifying the equation, we get 
 2x^2 - 3x - 3 + 1 = 0
 2x^2 - 3x - 2 = 0 
 After factoring the equation, we get
 (2x+1)(x-2) = 0 
 So, this means
 (2x+1) = 0 and (x-2) = 0 
 From this, we get 
 x = -1/2 and x = 2 
 Putting values of x = -1/2 in equation 2 
 y = 3(-1/2) - 1
 y = -2.5 
 Now, putting value of x = 2 in equation 2 
 y = 3(2) -1
 y = 5
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First, work out how much you need to add to A's x and y coordinates in order to get to point B from point A.

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x-difference = Bx - Ax = 3 - (-3) = 3 + 3 = 6
y-difference = By - Ay = 5 - 1 = 4

Now, if the point divides the segment AB in the ratio 2:3, then it is 2/(2+3) of the way along the line AB.

i.e. it is 2/5 of the way along the line AB.

We therefore need to add 2/5 of the x- and y-differences to point A to get point p:
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