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3 years ago

Help Help Help!!! :) solve the system of equations y=2x^2-3 y=3x-1

1 answer:

4 0

Solution:
y = 2x^2 - 3 ---- equation 1
y = 3x - 1 ------equation 2
Then we get,
2x^2 - 3 = 3x - 1
Now, simplifying the equation, we get
2x^2 - 3x - 3 + 1 = 0
2x^2 - 3x - 2 = 0
After factoring the equation, we get
(2x+1)(x-2) = 0
So, this means
(2x+1) = 0 and (x-2) = 0
From this, we get
x = -1/2 and x = 2
Putting values of x = -1/2 in equation 2
y = 3(-1/2) - 1
y = -2.5
Now, putting value of x = 2 in equation 2
y = 3(2) -1
y = 5

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Can u plz solve it asap with explanation. Thank you.

Shtirlitz [24]

okay so you should know that the formula for a triangle is:

A=1/2×b×h

where b is breadth and h is height

A is area

so they already gave the area which is 16.2 and they already gave a side ( doesn't matter if it's b or h in this question)

so we put these into the equation of the area of a triangle

A=1/2×b×h

16.2=1/2 × 6 × h

then you will solve algebraically to get 5.4cm which is you answer

to check if correct you can always put in all numbers in equation and you should get 16.2cm

In this case it's correct ✌

7 0

3 years ago

Read 2 more answers

P, Q, V, and K are collinear with V between K and P, and Q between V and K. If VP = 14x + 4, PK = x + 630, VQ = 17x + 6, and KQ

Ierofanga [76]

It's given in the question,

P, Q, V and K are collinear.

VP = 14x + 4

PK = x + 630

VQ = 17x + 6

KQ = 11x + 5

By segment addition postulate,

KQ + VQ + VP = KP

Substitute the values in the expression,

(11x + 5) + (17x + 6) + (14x + 4) = x + 630

(11x + 17x + 14x) + (5 + 6 + 4) = x + 630

42x + 15 = x + 630

42x - x = 630 - 15

41x = 615

x = $\frac{615}{41}$

x = 15

Therefore, value of VP = (14x + 4)

= 14(15) + 4

= 214 units

Learn more,

brainly.com/question/628239

3 0

3 years ago

PLEASE HELP!!!

lana [24]

EXPLANATION: By definition two lines are said to be parallel when the distance between two lines is same when measured from any point on one line.

However the criteria for intersection is that the distance between two lines should change and eventually should change to zero at intersection point.

Step-by-step explanation:

4 0

3 years ago

I NEED HELP FAST WHAT IS 80 + -9 - 5 + 89-66+44-9+87-100+213

kow [346]

Answer:

324 is ya answer!

5 0

3 years ago

Which equation has a graph that is perpendicular to the graph of -x + 6y = -12?

serious [3.7K]

Answer:

c) 6x + y = -52 is required equation perpendicular to the given equation.

Step-by-step explanation:

If the equation is of the form : y = mx + C.

Here m = slope of the equation.

Two equations are said to be perpendicular if the product of their respective slopes is -1.

Here, equation 1 : -x + 6y = -12

or, 6y = -12 + x

or, y = (x/6) - 2

⇒Slope of line 1 = (1/6)

Now, for equation 2 to be perpendicular:

Check for each equation:

a. x + 6y = -67 ⇒ 6y = -67 - x

or, y = (-x/6) - (67/6) ⇒Slope of line 2 = (-1/6)

but $\frac{1}{6} \times \frac{-1}{6} \neq -1$

b. x - 6y = -52 ⇒ -6y = -52 - x

or, y = (x/6) + (52/6) ⇒Slope of line 2 = (1/6)

but $\frac{1}{6} \times \frac{1}{6} \neq -1$

c. 6x + y = -52

or, y =y = -52 - 6x ⇒Slope of line 2 = (-6)

$\frac{1}{6} \times (-6) = -1$

Hence, 6x + y = -52 is required equation 2.

d. 6x - y = 52 ⇒ -y = 52 - 6x

or, y = 6x - 52 ⇒Slope of line 2 = (6)

but $\frac{1}{6} \times 6 \neq -1$

Hence, 6x + y = -52 is the only required equation .

3 0

3 years ago

Read 2 more answers