Answer:
(D)
Step-by-step explanation:
~a rational number....I hope it helps
Complete question is;
The terminal side of angle θ in standard position, intersects the unit circle at P(-10/26, -24/26). What is the value of csc θ?
Answer:
csc θ = -13/12
Step-by-step explanation:
We know that in a unit circle;
(x, y) = (cos θ, sin θ)
Since the the terminal sides intersects P at the coordinates P(-10/26, -24/26), we can say that;
cos θ = -10/26
sin θ = -24/26
Now we want to find csc θ.
From trigonometric ratios, csc θ = 1/sin θ
Thus;
csc θ = 1/(-24/26)
csc θ = -26/24
csc θ = -13/12
As it can be seen in the figure above, the figure A'B'C' is bigger than ABC due to dilation.
If we are to measure the side AB, that would be 3. Also, we have A'B' measured to be 6 units.
The dilation factor is calculated by dividing the lengths of the corresponding sides. In this example that would be,
d = A'B' / AB = 6 / 3 = 2
ANSWER: 2
Answer:
k = 3
Step-by-step explanation:
Expanding the first term, we find 1/x at 10(kx)²(1/x)³ = 10k²/x
Expanding the first term, we find 1/x at 8*1⁷(-2/x)¹ = -16/x
Then
10k² - 16 = 74
k = 3
There are 6 different ways:
23,598
23,958
25,398
25,938
29,538
29,358
