<em>HOPE</em><em> </em><em>THIS</em><em> </em><em>WILL</em><em> </em><em>HELP</em><em> </em><em>U</em><em>.</em><em>.</em><em>.</em>
I believe the answer the answer is 5.1 b
Let x represent first number in pair and y represent second number. We can see that x numbers are increasing by 1 on each next pair. y numbers are square of 0,2,4,6 and 8
Knowing all of that let "n" represent the position of the pair starting from 0!
than we can write that the rule is:
(n,(2n)^2)
The solution would be x > 1 sorry if its wrong but hope it helps