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AnnyKZ [126]
3 years ago
15

Predict the molecular geometry for each. Match the words in the left column to the appropriate blanks in the sentences on the ri

ght. ResetHelp T-shaped square pyramidal tetrahedral linear trigonal bipyramidal seesaw square planar trigonal pyramidal octahedral bent trigonal planar The molecule BrO2− has a(n) The molecule B r O 2 − has a(n) blank molecular geometry. molecular geometry. The molecule ClO3− has a(n) The molecule C l O 3 − has a(n) blank molecular geometry. molecular geometry. The molecule CH3+ has a(n) The molecule C H 3 + has a(n) blank molecular geometry. molecular geometry. The molecule BrF3 has a(n) The molecule B r F 3 has a(n) blank molecular geometry. molecular geometry. The molecule XeF2 has a(n) linearThe molecule X e F 2 has a(n) blank molecular geometry. molecular geometry. The molecule AsF3 has a(n) The molecule A s F 3 has a(n) blank molecular geometry. molecular geometry.
Chemistry
1 answer:
Tatiana [17]3 years ago
4 0

Answer:

BrO2-bent

ClO3−trigonal pyramidal

CH3+trigonal planar

BrF3 T-shaped

XeF2 linear

AsF3. trigonal pyramidal

Explanation:

For BrO2-, there are two shapes possible for any three atom molecule; linear or bent. In this case, starting with 7 electrons around a Br atom and at least two formal bonds it is safe to say that it will be bent because there will have to be an accommodated one lone pair on the central atom Br.

Based on VSEPR Theory the electron clouds on atoms and lone pair of electrons around the central Cl atom will repel each other. As a result they will be pushed apart giving the ClO3- molecule a trigonal pyramidal geometry or shape.

Carbon has 4 valence electrons. But in CH3+, a positive charge makes the number of available electrons 3. Hence carbon forms 3 single bonds with H to form a planar structure with sp2 hybridization.

BrF3 contains three bonded and two nonbonded electron domains, giving a trigonal bipyramidal electron domain geometry and a T shaped molecular geometry. The bond angles are compressed relative to those ones in a perfect trigonal bipyramid due to lone pairs spreading out more in space than bonded pairs.

XeF2 has 22 valence electrons, out of which there are three lone pairs of electrons. Its hybridization is sp3d. According to the VSEPR theory, The molecular geometry of the molecule is linear. The bond angle of F-Xe-F is 180 degrees.

The molecule AsF3 has four electron domains around the central atom. Hence the electron domain geometry is Tetrahedral. As there is one non bonded electron pair, the molecular geometry is thus Trigonal pyramidal.

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350.64g

Explanation:

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Select the correct hybridization for the central atom based on the electron geometry cocl2 (carbon is the central atom).
Rainbow [258]
In this compound (Phosgene) the central atom (carbon is Sp² Hybridized).

Sp, Sp² and Sp³ can be calculated very simply by doing three steps, 

Step 1:
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Step 2:
          Count lone pair of electron, each lone pair counts for s and p. In this case there is no lone pair of electron on carbon, so not included.

Step 3:
          Count single bonds for s and p. As we have already assigned s to the double bond, now one p for one single bond, and other p for the other single bond.

Result:
          So, we counted 1 s for double bond, 1 p for one single and other p for second single bond. As a whole we got,

                                                       Sp²

Practice:
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Answer:

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Explanation:

All experimental measures are subject to errors.

Even when the colorimeter is properly calibrated and correctly used, there are random errors.

Random errors are are due to fortuitous factors, such as minor oversight by the observer or small changes of the conditions under which the measurements are made.

You can minimize the random errors by increasing the number of measurements, because the random errors tend to happen in any direction; some measures will be greater and other will be less than the true value.

Chance will make that errors in on direction cancel with errors in the opposed direction, making the average the best measure.

Thus, <em>Jay</em>, by <em>repeating the experiment five times and taking the average measurement</em>, is making that<em> his measurements are</em> <em>least likely to contain random errors.</em>

3 0
4 years ago
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