Answer:
- AgNO₃ (aq) + KCl (aq) → AgCl (s) + KNO₃ (aq)
Explanation:
In a <em>solubility table</em> you find:
- AgNO₃ (silver nitrate) is highly soluble
- KCl (potassium chloride) is soluble
- AgCl (silver chloride) is insoluble
- KNO₃ (potassium nitrate) is soluble
In a chemical equation the states of soluble compounds is identified as aqeous, using the letter "aq" in parenthesis, and the state of insoluble compounds is identified as solid, using "s" in parenthesis.
Then, the reaction showing the states of the reactants and products is:
- AgNO₃ (aq) + KCl (aq) → AgCl (s) + KNO₃ (aq)
Answer:
Need more information.
Explanation:
I believe you either left out info or explained the question confusingly.
I believe the answer is carbon atoms
Answer:
2812.6 g of H₂SO₄
Explanation:
From the question given above, the following data were obtained:
Mole of H₂SO₄ = 28.7 moles
Mass of H₂SO₄ =?
Next, we shall determine the molar mass of H₂SO₄. This can be obtained as follow:
Molar mass of H₂SO₄ = (1×2) + 32 + (16×4)
= 2 + 32 + 64
= 98 g/mol
Finally, we shall determine the mass of H₂SO₄. This can be obtained as follow:
Mole of H₂SO₄ = 28.7 moles
Molar mass of H₂SO₄ =
Mass of H₂SO₄ =?
Mole = mass / Molar mass
28.7 = Mass of H₂SO₄ / 98
Cross multiply
Mass of H₂SO₄ = 28.7 × 98
Mass of H₂SO₄ = 2812.6 g
Thus, 28.7 mole of H₂SO₄ is equivalent to 2812.6 g of H₂SO₄
When you drop iodine on a leaf you may observe a colour change of orange/brown to a blue/black complex.
This is because in the leaf there are starch molecules that form a blue/black complex with the starch molecules.
hope that helps :)
