Answer:
1/3p0
Explanation:
The combined gas law:
P1V1/T1 = P2V2/T2, where P, V and T are Pressure, Volume, and Temperature. Temperature must always be in Kelvin. The subscriopts 1 and 2 are for initial (1) and final (2) conditions.
In this case, temperature is constant (adiabatically). V1 = 2.0L and V2 = 6.0L. I'll assume P1 = p0.
Rearrange the combined gas law to solve for final pressure, P2:
P1V1/T1 = P2V2/T2
P2 = P1*(V1/V2)*(T2/T1) [Note how I've arranged the volume and temoperature terms - as ratios. This helps us understand what the impact of raising or lowering one on the variables will do to the system].
No enter the data:
P2 = P1*(V1/V2)*(T2/T1): [Since T2 = T1, the (T2/T1) terms cancels to 1.]
P2 = p0*(2.0L/6.0L)*(1)
P2 = (1/3)p0
The final pressure is 1/3 the initial pressure.
Answer:
Chewing in the mouth breaks food into small pieces.
Explanation:
Hope this is one of the answer choices!
Answer:
The denominator B = P1V1
Explanation:
We'll begin by writing the combine gas equation. This is shown below:
P1V1/T1 = P2V2/T2
Where:
P1 is the initial pressure.
V1 is the initial volume.
T1 is the initial temperature.
P2 is the final pressure.
V2 is the final volume.
T2 is the final temperature.
Now let us make T2 the subject of the formula to obtain our desired result. This is illustrated below:
P1V1/T1 = P2V2/T2
Cross multiply to express in linear form
P1V1T2 = P2V2T1
Divide both side by P1V1
T2 = P2V2T1/P1V1
From the above illustration,
The numerator A = P2V2T1
The denominator B = P1V1
The frequency of the wavelength is 551 because the green line is on it
Explanation:
In a covalent bond the electrons are simultaneously attracted by the two atomic nuclei.
