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vagabundo [1.1K]
3 years ago
13

The accepted value is 29.35. Which correctly describes this student's experimental data?

Chemistry
1 answer:
kkurt [141]3 years ago
3 0

Answer:

- Both accurate and precise.

Explanation:

The experimental data is characterized as the data that is generated through a specific test or measurement with the purpose of analysis or evaluation. As per the question, the minuteness of the given data(29.27, 29.32, and 29. 27)most aptly describes that the experimental data collected by the student possesses 'accuracy and precision' apt and specific. It would yield the most worthy and reliable conclusion.

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How do anion formation and valence electrons relate?
sveta [45]

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Explanation:

Anions are negatively charged species of an ions. Anions are formed when atoms with nearly complete octet gains electrons.

Answer 2: Emission spectrum

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When ever electron jumps from higher energy to lower energy level energy is emitted out in the form of light.The wavelength of the light is given as \lambda:

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5 0
3 years ago
Balance the redox reaction in alkaline medium & identify the oxidizing & reducing agents
Darya [45]

The balanced redox equation of the reaction is given below:

  • I⁻ + 2 MnO₄ + H₂O → IO₃⁻ + 2 MnO₂ + 2 OH⁻

The oxidizing agent is MnO₄ while the reducing agent is I⁻.

<h3>What are redox equations?</h3>

Redox equations are equations in which oxidation and reduction reactions occur together.

Redox reactions can take place in alkaline or acidic mediums.

The balanced redox equation of the reaction is given below:

  • I⁻ + 2 MnO₄ + H₂O → IO₃⁻ + 2 MnO₂ + 2 OH⁻

The oxidizing agent is MnO₄ while the reducing agent is I⁻

In conclusion, a balanced redox equation is one in which the atoms and the change in oxidation state is equal on both sides of the reaction.

Learn more about redox equations at: brainly.com/question/27239694

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8 0
2 years ago
a sample of cobalt (specific heat of Co=0.418J/G C )at 100.0 C is dropped into a calorimeter containing 500.0 mL of water at 21.
Alex17521 [72]

Answer:

m_{Co}=6998g=7.0kg

Explanation:

Hello there!

In this case, according to this equilibrium temperature problem, we can set up the following equation to relate the mass, specific heat and temperature change:

Q_{Co}=-Q_{w}\\\\m_{Co}C_{Co}(T_f-T_{Co})=-m_{w}C_{w}(T_f-T_{w})

Thus, we solve for the mass of cobalt as shown below:

m_{Co}=\frac{-m_{w}C_{w}(T_f-T_{w})}{C_{Co}(T_f-T_{Co})} \\\\m_{Co}=\frac{-500.00g*4.184J/g\°C(67.1\°C-21.1\°C)}{0.418J/g\°C(67.1\°C-100\°C)} \\\\m_{Co}=6998g=7.0kg

Best regards!

7 0
3 years ago
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