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dlinn [17]
3 years ago
10

A cylinder containing 20.0 L of compressed nitrogen is connected to an empty (evacuated) vessel with an unknown volume. The gas

pressure in the cylinder starts at 25 atm and drops to 2 atm without a change in temperature. Determine the volume of the vessel.
Chemistry
1 answer:
Nonamiya [84]3 years ago
3 0

Answer:

The new volume of the vessel is 250 L

Explanation:

Step 1: Data given

The volume of the cylinder = 20.0 L

The initial pressure of the gas = 25 atm

The pressure drops to 2 atm

Step 2: Calculate the volume of the vessel

P1*V1 = P2*V2

⇒with P1 = the initial pressure = 25 atm

⇒with V1 = the initial volume = 20.0 L

⇒with P2 = the final pressure = 2 atm

⇒with V2 = the final volume = TO BE DETERMINED

25 atm* 20.0 L = 2.0 atm * V2

V2 = 250 L

The new volume of the vessel is 250 L

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How to find nuetrons
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2 years ago
Problem PageQuestion Aqueous sulfuric acid will react with solid sodium hydroxide to produce aqueous sodium sulfate and liquid w
quester [9]

Answer:

0.72g

Explanation:

Step 1:

We'll begin by writing a balanced equation for the reaction. This is illustrated below:

H2SO4 + 2NaOH —> Na2SO4 + 2H2O

Step 2:

Determination of the mass of sulphuric acid (H2SO4) and the mass of sodium hydroxide (NaOH) that reacted from the balanced equation. This is illustrated below:

Molar Mass of H2SO4 = (2x1) + 32 +(16x4) = 2 + 32 + 64 = 98g/mol

Molar Mass of NaOH = 23 + 16 + 1 = 40g/mol

Mass of NaOH from the balanced equation = 2 x 40 = 80g

Step 3

Determination of the limiting reactant. To do this, we need to know which of the reactant is excess.

Now let us consider using all of the mass of NaOH given to see if there will be left over for H2SO4. This is illustrated below:

From the balanced equation above,

98g of H2SO4 required 80g of NaOH.

Therefore, Xg of H2SO4 will require 1.6g of NaOH i.e

Xg of H2SO4 = (98x1.6)/80

Xg of H2SO4 = 1.96g

Now comparing the mass of H2SO4 that reacted ( i.e 1.96g) and the mass of H2SO4 given ( i.e 2.94g), we can see clearly that there are left over ( i.e 2.94 - 1.96 = 0.98g) of H2SO4. Therefore, H2SO4 is the excess reactant and NaOH is the limiting reactant.

Step 4:

Determination of the mass of water produced from the reaction. This is illustrated below:

The balanced equation for the reaction is given below:

H2SO4 + 2NaOH —> Na2SO4 + 2H2O

Molar Mass of H2O = (2x1) + 16 = 2 + 16 = 18g/mol

Mass of H2O from the balanced equation = 2 x 18 = 36g

From the balanced equation above,

80g of NaOH reacted to produced 36g of H2O.

Therefore, 1.6g of NaOH will react to produce = (1.6 x 36)/80 = 0.72g of H2O.

Therefore, the maximum mass of water (H2O) produced by the chemical reaction of aqueous sulfuric acid with solid sodium hydroxide is 0.72g

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3 years ago
What is the genetic makeup of both parents ?
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Answer:

A, T, C y G, son las "letras" del código del ADN; representan los compuestos químicos adenina (A), timina (T), citosina (C) y guanina (G), respectivamente, que constituyen las bases de nucleótidos del ADN. ...El código genético es el conjunto de reglas que define cómo se traduce una secuencia de nucleótidos en el ARNm a una secuencia de aminoácidos en una proteína

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3 years ago
A student wants to make a 0.600 M aqueous solution of barium sulfate, BaSO4, and has a bottle containing 12.00 g of barium sulfa
love history [14]

<u>Answer: </u>The volume of the solution is 85.7 mL

<u>Explanation:</u>

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

\text{Molarity of solution}=\frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (mL)}} .....(1)

We are given:

Molarity of solution = 0.600 M

Given mass of BaSO_4 = 12.00 g

We know, molar mass of BaSO_4=[(1\times 137.33)+(1\times 32.07)+(4\times 16)]=233.4g/mol

Putting values in equation 1, we get:

0.600=\frac{12.00\times 1000}{233.4\times \text{Volume of solution}}\\\\\text{Volume of solution}=\frac{12.00\times 1000}{233.4\times 0.600}=85.68mL=85.7mL

The rule of significant number that is applied for the problems having multiplication and division:

The least number of significant figures in any number of the problem determines the number of significant figures in the answer.

Here, the least number of significant figures is 3 that is determined by the number, 0.600. Thus, the answer must have these many significant figures only.

Hence, the volume of the solution is 85.7 mL

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2 years ago
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