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OleMash [197]
3 years ago
13

I AM GIVING 95POINTS HELP PLEASE!!

Physics
2 answers:
ValentinkaMS [17]3 years ago
4 0

This is a fun question - your science teacher is creative!


First is easy, 25000 feet converts to 7620 meters


Potential energy is a product of mass, gravity and height. In this case, mass is 90Kg and height is 7620m. gravity on earth is 9.8m/s2.


Potential energy = 90(9.8)(7620) = 6720840J



By Newton 2nd law, force is equal to mass times acceleration.


Gravity force = mass*gravity


= 90(9.8) = 882N



Acceleration when he leaves the plane is gravity, 9.8m/s2



With no wind resistance, the acceleration is constant at 9.8.


Using kinematic equation, v2 = u2 + 2as where u is initial velocity, v is final velocity, a is acceleration and s is distance traveled.


In this case, u=0, a=9.8, s=7620


v^2 = 2(9.8)(762) = 149352


final velocity = sqrt (149352) = 386.5m/s


150MPH converts to 67m/s.



If he is falling at a constant speed of 150MPH, then he is not accelerating.



As he is not accelerating, the net force = gravity force - wind resistance = 0


wind resistance = gravity force


= 90(9.8) = 882N



If there is no wind resistance, by conservation of energy,


final Kinetic Energy = initial Potential energy


= mass * gravity * height


= 90*9.81*7620


= 6720840J


He is unhurt because the safety net provides a soft landing. It decelerates his momentum gradually over time to avoid injury.


Firlakuza [10]3 years ago
3 0

25,000 Feet = 7620m


PE = mgh where m is mass, g is gravity accel: 9.8 n h is height


= 90 x 9.8 x 7620


= 6720840J


= 6.72MJ


F = ma where m is mass, a is accel = gravity = 9.8


= 90 x 9.8


= 882N


Accel = gravity = 9.8m/s^2


KE = 1/2mv^2 where m is mass n v is vel


if no wind resistance, PE leaving airplane = KE at net


6720840 = 1/2 x 90 x v^2


v^2 = 149352


v = 386.5m/s


150MPH=67m/s


@150MPH, his speed is not changing so accel=0


accel=0, force=0 by newton's second law


force=0 when wind resistance = gravity = 9.8m/s^2


by conservation of energy, Luke's KE = PE = mgh = 6720840J


he was unhurt cuz' his momentum was absorbed by the net

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