Answer:
The First is an example of acceleration, the second is an example of velocity
Answer:
Time=8.23880597 seconds
Explanation:
Quantity of charge(q)=2.76c
Current(I)=0.335A
Time(t)=?
t=q/I
t=2.76/0.335
t=8.23880597seconds
Answer:
(a) A = 0.0800 m, λ = 20.9 m, f = 11.9 Hz
(b) 250 m/s
(c) 1250 N
(d) Positive x-direction
(e) 6.00 m/s
(f) 0.0365 m
Explanation:
(a) The standard form of the wave is:
y = A cos ((2πf) t ± (2π/λ) x)
where A is the amplitude, f is the frequency, and λ is the wavelength.
If the x term has a positive coefficient, the wave moves to the left.
If the x term has a negative coefficient, the wave moves to the right.
Therefore:
A = 0.0800 m
2π/λ = 0.300 m⁻¹
λ = 20.9 m
2πf = 75.0 rad/s
f = 11.9 Hz
(b) Velocity is wavelength times frequency.
v = λf
v = (20.9 m) (11.9 Hz)
v = 250 m/s
(c) The tension is:
T = v²ρ
where ρ is the mass per unit length.
T = (250 m/s)² (0.0200 kg/m)
T = 1250 N
(d) The x term has a negative coefficient, so the wave moves to the right (positive x-direction).
(e) The maximum transverse speed is Aω.
(0.0800 m) (75.0 rad/s)
6.00 m/s
(f) Plug in the values and find y.
y = (0.0800 m) cos((75.0 rad/s) (2.00 s) − (0.300 m⁻¹) (1.00 m))
y = 0.0365 m
Answer:
about 4.74 seconds
Explanation:
The time to fall distance d from height h is given by ...
t = √(2d/g)
t = √(2·110 m/(9.8 m/s^2)) ≈ 4.74 s
It will take the car about 4.74 seconds to fall 110 meters to the river.
__
We assume the car's speed is horizontal, so does not add or subtract anything to/from the time to fall from the height.
Answer:
Ahhhhhh ano wala dito ang answer
