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mel-nik [20]
3 years ago
14

Lcm of 120,5200 and 40​

Mathematics
1 answer:
kiruha [24]3 years ago
4 0
Ok because what does this even mean
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1 / f = 1 / a + 1 / b
Sphinxa [80]

That equation can represent the relationship among the image distance,
object distance, and focal length of a lens. 

It could describe the effective resistance of two resistors in parallel, the
effective inductance of two coils in parallel, or the effective capacitance
of two capacitors in series. 

Thanks for sharing it.  Now, did you have a question to ask ?

6 0
3 years ago
The number 900 is increased by 20% and then decreased by 20%. Find the new number.(the ans is 864 apparently:/ I need steps)
Georgia [21]

Step-by-step explanation:

if 900 is increased by 20% then

120/100×900=1080

Decreasing it by 20% then

80/100×1080=864

5 0
2 years ago
What is a discount rate
8090 [49]
The Federal Reserve sets an minimum rate to for lending to other banks.
4 0
3 years ago
Read 2 more answers
The tension t in a spring varies directly with the distance d the spring is stretched. If the
yarga [219]

Answer:

t = 21d

Step-by-step explanation:

Here tension and distance are denoted t by d  and  respectively. Since  t varies directly with d , then the relation between  t and d is k=td Given that, for the tension 42 pounds, the spring is stretched 2 inches. Substituting  t = 42 and d= 2 into  t = kd find the value of k . Therefore,

42= K (2)

K=\frac{42}{2}

K= 21

Thus the relationship is t = 21d

(Hope this helps can I pls have brainlist (crown)☺️)

7 0
2 years ago
Write equation for the line that is perpendicular to the y axis and passing through (5,1)
Alla [95]

Answer:

Step-by-step explanation:

A line perpendicular to the y-axis, which is vertical, is a line that is horizontal. Perfectly horizontal lines always have a slope of 0. Thus, the equation of the line perpendicular to the one given and passing through the given point (5, 1) is

y - 1 = 0(x - 5) and

y - 1 = 0x - 0 and

y - 1 = 0 so

y = 1 is the equation you're looking for.

3 0
3 years ago
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