Represent these consecutive numbers (assuming that they are all integers):
x
x+1
x+2
x+3
x+4
x+5
and so on
x+8
x+9 is the tenth number. x+9 = 10, so x = 9.
Think of it this way: there are 10 consecutive numbers, and the last one is 10.
Working backwards, we get the sequence 10, 9, ... 3, 2, 1.
The sum of such an arith sequence is equal to the count of the numbers times the average of the first and last terms:
sum here = 10(1+10)/2 = 5(11) = 55 (answer)
WHAT IS THIS LANGUAGE ? PLEASE TRY TO USE ENGLISH !
Yeah Imao you usually do these type of questions on a calculator but I've tried writing it on a calculator and it keeps on saying "error" so I'm gonna guess the question is wrong or sth
but if you type out the question without the bracket before the 12 you'll get 6.63
anyway hope this helps- have a good day bro cya)
Answer: D
Step-by-step explanation:
You have to divide both the numerator and the denominator and you get 1/3 and thats the simplest form
