It is known that 32g of oxygen takes up 24 litres of space at 25oC. Calculate the volume of oxygen that is needed to react compl

Question

3 years ago

8

etely with 12g of magnesium.

1 answer:

Gwar [14] · Answer 1 · 2022-06-30T15:47:57+03:00

6 L of oxygen (O₂)

Explanation:

We have the following chemical reaction:

2 Mg + O₂ → 2 MgO

Now we calculate the number of moles of magnesium:

number of moles = mass / molar weight

number of moles of Mg = 12 / 24 = 0.5 moles

Taking in account the chemical reaction we devise the following reasoning:

if 2 moles of Mg react with 1 mole of O₂

then 0.5 moles of Mg react with X moles of O₂

X = (0.5 × 1) / 2 = 0.25 mole of O₂

mass = number of moles × molar weight

mass of O₂ = 0.25 × 32 = 8 g

Knowing the information given by the problem that 32 g of O₂ takes up 24 liters of space, we devise the following reasoning:

if 32 g of O₂ takes up 24 liters of space

then 8 g of O₂ takes up Y liters of space

Y = (8 × 24) / 32 = 6 L of O₂

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