How many ounces is 68 g? O A. 0.42 oz O B. 28.3 oz O C. 4.8 oz O D. 2.4 oz

Organic protein catalysts are called: carbohydrates amino acids enzymes lipids

Fittoniya [83]

Answer:

Enzymes.

Explanation:

That would be enzymes. They increase the rate of chemical reactions in cells.

7 0

3 years ago

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What is the minimum volume of 5.50 M HCl necessary to neutralize completely the hydroxide in 718.0 mL of 0.183 M NaOH

Deffense [45]

The volume of HCl required is 23.89 mL

Calculation of volume:

The reaction:

$HCl + NaOH \rightarrow NaCl + H_2O$

As HCl and NaOH react in 1 : 1 ratio.

Volume of NaOH= 718 mL

Concentration= 0.183M

Volume of HCl= ?

Concentration= 5.50M

Using the dilution formula:

$M_1\times V_1(NaOH)= M_2\times V_2(HCl)$

$0.183\times 718= 5.50 \times V_2\\V_2=\frac{131.394}{5.50} \\V_2 = 23.89 \,mL$

Therefore,

Volume of HCl required will be 23.89 mL.

Learn more about neutralization reaction here,

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6 0

1 year ago

Open the Balancing Chemical Equations interactive and select Introduction mode. Then choose Separate Water. Adjust the coefficie

aleksklad [387]

Explanation:

1. Water decomposition

Decomposition reactions are represented by-

The general equation: AB → A + B.

Various methods used in the decomposition of water are -

Electrolysis
Photoelectrochemical water splitting
Thermal decomposition of water
Photocatalytic water splitting

Water decomposition is the chemical reaction in which water is broken down giving oxygen and hydrogen.

The chemical equation will be -

$H_2O + H_2 + O_2$

Hence, balancing the equation we need to add a coefficient of 2 in front of $H_2O$ on right-hand-side of the equation and 2 in front of $H_2$ on left-hand-side of the equation.

∴The balanced equation is -

$2 H_2O$ → $2 H_2 + O_2$

2. Formation of ammonia

The formation of ammonia is by reacting nitrogen gas and hydrogen gas.

$N_2 + H$ → $NH_3$

Hence, for balancing equation we need to add a coefficient of 3 in front of hydrogen and 2 in front of ammonia.

∴The balanced chemical equation for the formation of ammonia gas is as follows -

$N_2+3H$ → $2NH_3$ .

When 6 moles of $N_2$ react with 6 moles of $H_2$ 4 moles of ammonia are produced.

5 0

2 years ago

Calculate the reaction quotient Qp for the following redox reaction: 14H+ + Cr2O72- + 6Cl- ----> 2Cr3+ + 3Cl2 + 7H2O The reac

stich3 [128]

Answer:

Value of $Q_{p}$ for the given redox reaction is $1.0\times 10^{-8}$

Explanation:

Redox reaction with states of species:

$14H^{+}(aq.)+Cr_{2}O_{7}^{2-}(aq.)+6Cl^{-}(aq.)\rightarrow 2Cr^{3+}(aq.)+3Cl_{2}(g)+7H_{2}O(l)$

Reaction quotient for this redox reaction:

$Q_{p}=\frac{[Cr^{3+}]^{2}.P_{Cl_{2}}^{3}}{[H^{+}]^{14}.[Cr_{2}O_{7}^{2-}].[Cl^{-}]^{6}}$

Species inside third braket represent concentration in molarity, P represent pressure in atm and concentration of $H_{2}O$ is taken as 1 due to the fact that $H_{2}O$ is a pure liquid.

$pH=-log[H^{+}]$

So, $[H^{+}]=10^{-pH}$

Plug in all the given values in the equation of $Q_{p}$ :

$Q_{p}=\frac{(0.10)^{2}\times (0.010)^{3}}{(10^{-0.0})^{14}\times (1.0)\times (1.0)^{6}}=1.0\times 10^{-8}$

7 0

2 years ago

CH3CO2H(aq) + H2O(l) ⇄ CH3CO2-(aq) + H3O+(l)

Evgen [1.6K]

Correct Answer: Option C: The equilibrium position will shift to the right toward the products.

Reason:
1) This problem is based on Le Chatelier's principle. It is stated as 'any changes in the temperature, volume, or concentration of a system will result in predictable and opposing changes in the system in order minimize this change and achieve a new equilibrium state.'

2) In present case, the reaction involved is:
 CH3CO2H(aq) + H2O(l) ⇄ CH3CO2-(aq) + H3O+(l)
Hence, when the concentration of acetic acid (reactant) is increased, the equilibrium will shift to right to minimize the effect of change in concentration of reactant.

4 0

2 years ago