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iris [78.8K]
3 years ago
10

Please help!!!!!!!!! ASAP!!!

Chemistry
1 answer:
Ad libitum [116K]3 years ago
4 0

Answer:

0.00505

Explanation:

You can google the answer or try to learn how to convert it

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What is the concentration of a sodium hydroxide solution if 14.5 mL of it are exactly neutralized by 30.0 mL of a 0.500 M hydroc
rusak2 [61]

Answer:

1.03 M

Explanation:

Step 1: Write the balanced equation

NaOH + HCl ⇒ NaCl + H₂O

Step 2: Calculate the reacting moles of HCl

30.0 mL (0.0300 L) of 0.500 M HCl react.

0.0300 L × 0.500 mol/L = 0.0150 mol

Step 3: Calculate the moles of NaOH that react with 0.0150 moles of HCl

The molar ratio of NaOH to HCl is 1:1. The moles of NaOH that react are 1/1 × 0.0150 mol = 0.0150 mol.

Step 4: Calculate the molar concentration of NaOH

0.0150 moles of NaOH are in 14.5 mL (0.0145 L).

M = 0.0150 mol/0.0145 L = 1.03 M

4 0
3 years ago
Will mark as Brainliest.
stealth61 [152]
The answer you are looking for is A. If you need me to show you how I got the answer let me know. :)
3 0
3 years ago
During _____, bonds between monomers are broken by adding water.
cricket20 [7]
During _<span>A.   hydrolysis</span>, bonds between monomers are broken by adding water.
Prefix "hydro-" means water.
"-lysis" - disintegration.
3 0
3 years ago
What is the correct name of this compound?
Reika [66]

Answer:

7. 3–ethyl–6 –methyldecane

8. 5–ethyl–2,2–dimethyl–4–propyl–4 –heptene

Explanation:

It is important to note that when naming organic compounds having two or more different substituent groups, we simply name them alphabetically.

The name of the compound given in the question above can be written as follow:

7. Obtaining the name of the compound.

Compound contains:

I. Decane.

II. 3–ethyl.

III. 6 –methyl.

Naming alphabetically, we have

3–ethyl–6 –methyldecane

8. Obtaining the name of the compound.

Compound contains:

I. 2,2–dimethyl.

II. 4–propyl.

III. 4 –heptene.

IV. 5–ethyl.

Naming alphabetically, we have

5–ethyl–2,2–dimethyl–4–propyl–4 –heptene

8 0
3 years ago
An atom or ion has 41 neutrons, 36 protons, and 36 electrons. Identify the element symbol, and determine the mass number
igor_vitrenko [27]

Answer:

Element symbol: Kr.

Mass number: 77.

Charge : 0.

Explanation:

Hello,

In this case, since such substance has the same amount of protons and electrons we can infer it is an atom whose number of neutrons is defined by considering its atomic mass or mass number and atomic number which is actually equal to the number of protons and electrons (36):

neutrons=atomic\ mass - atomic\ number

In such a way, solving for the atomic mass we obtain:

atomic\ mass=neutrons+ atomic\ number\\\\atomic\ mass=41+36=77

It means that the element is krypton (Kr) as it has 36 electrons and protons so its charge is 0.

Best regards.

5 0
3 years ago
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