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Lina20 [59]
3 years ago
5

DESCRIBE floods and droughts. What are their effects? EXPLAIN how they can be prevented

Physics
1 answer:
BabaBlast [244]3 years ago
3 0

Answer:

<u>EFFECTS: ( doughts)</u>

  1. There would be less water in the river for you and other people who live along the river to use.
  2. If we use too much water during times of normal rainfall, we might not have enough water when a drought happens.

<u>EFFECTS:( FLOODS)</u>

  1. The immediate impacts of flooding include loss of human life, damage to property, destruction of crops, loss of livestock, and deterioration of health conditions owing to waterborne diseases.
  2. power plants, roads and bridges are damaged and disrupted, some economic activities may come to a standstill, people are forced to leave their homes and normal life is disrupted.

How to prevent from flooding is :

  1. Construct buildings above flood levels.
  2. Tackle climate change

How to prevent from droughts :

  1. drought trends that may occur based on statistical and actual weather forecasts.
  2. In the U.S., the U.S. Drought Monitor provides a day-by-day visual of the drought conditions around the country.

* Hopefully this helps:) Mark me the brainliest:)!!!

~234483279c20~

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A squirrel is trying to locate some nuts he buried for the winter. He moves 4.3 m to the right of a stone and dogs unsuccessfull
krek1111 [17]

Answer:

The total displacement from the starting point is 1.5 m.

Explanation:

You need to sum and substract, depending on the movement (to the right, sum; to the left, substract).

First, it moves 4.3 m right and return 1.1 m. So the new distance from the starting point is 3.2 m.

Second, it moves 6.3 m right, so the new distance is 9.5 m.

Finally it moves 8 m to the left, so 9.5 m - 8 m= 1.5 m.

Summarizing, at the end the squirrel is 1.5 m from its starting point.

8 0
4 years ago
How do u find net force?
Damm [24]
1Draw a quick sketch of the object.
2Draw an arrow showing every force acting on the object.
3<span>To calculate the net force, add any vectors acting on the same axis (x and y), making sure to pay attention to the directions.
Hope this helps :)
</span>
7 0
3 years ago
In 2017, the company SpaceX became the first private company to send supplies to the International Space Station with a reusable
pav-90 [236]

Answer:

Approximately 3.98\; \rm m \cdot s^{-2}.

Assumption: air resistance on the rocket is negligible. Take g = \rm 9.81\; m \cdot s^{-2}.

Explanation:

By Newton's Second Law of Motion, the acceleration of the rocket is proportional to the net force on it.

\displaystyle \text{Acceleration} = \frac{\text{Net Force}}{\text{Mass}}.

Note that in this case, the uppercase letter \rm M in the units stands for "mega-", which is the same as 10^6 times the unit that follows. For example, \rm 1\; Mg = 10^6\; g, while \rm 1\; MN = 10^6\; N.

Convert the mass of the rocket and the thrust of its engines to SI standard units:

  • The standard unit for mass is kilograms: \displaystyle m = \rm 552\; Mg = 552 \times 10^6\; g \times \frac{1\; \rm kg}{10^3\; g}  = 552 \times 10^3 \; kg.
  • The standard for forces (including thrust) is Newtons: \text{Thrust} = \rm 7.61 \; MN = 7.61 \times 10^6\; N.

At launch, the velocity of the rocket would be pretty low. Hence, compared to thrust and weight, the air resistance on the rocket would be pretty negligible. The two main forces that contribute to the net force of the rocket would be:

  • Thrust (which is supposed to go upwards), and
  • Weight (downwards due to gravity.)

The thrust on the rocket is already known to be \rm 7.61 \times 10^6\; N. Since the rocket is quite close to the ground, the gravitational acceleration on it should be approximately 9.81\; \rm m \cdot s^{-2} = 9.81 \; N \cdot kg^{-1}. Hence, the weight on the rocket would be approximately 9.81\; \rm N \cdot kg^{-1} \times 552 \times 10^3\; kg = 5.41412\times 10^6\; N.

The magnitude of the net force on the rocket would be

\begin{aligned}&\text{Thrust} - \text{Weight} \\ &= 7.61 \times 10^6\; \rm N - 5.41412\times 10^6\; N \\ &\approx 2.19 \times 10^6\; \rm N\end{aligned}.

Apply the formula \displaystyle \text{Acceleration} = \frac{\text{Net Force}}{\text{Mass}} to find the net force on the rocket. To make sure that the output (acceleration) is in SI units (meters-per-second,) make sure that the inputs (net force and mass) are also in SI units (Newtons for net force and kilograms for mass.)

\begin{aligned}\displaystyle &\text{Acceleration} \\ &= \frac{\text{Net Force}}{\text{Mass}} \\ &= \frac{2.19 \times 10^6\; \rm N}{552 \times 10^3\; \rm kg}  \\ &\approx \rm 3.98\; \rm m \cdot s^{-2}\end{aligned}.

6 0
3 years ago
Which tuning fork test evaluates conductive and sensorineural hearing loss in both ears at the same time
Flura [38]

The Rinne and Weber tests are frequently used to detect conductive and sensorineural deafness.

Another test to assess conductive and sensorineural hearing impairments is the Weber test. When sound waves cannot flow from the middle ear to the inner ear, conductive hearing loss results.

This may be brought on by issues with the eardrum, middle ear, or ear canal, such as an infection. A helpful, quick, and easy screening test for determining hearing loss is the Weber test.

The test can identify unilateral sensorineural and conductive hearing loss. Conduction hearing is mediated by the middle and outer ear. A tuning fork is used in the Weber test, a hearing screening procedure. It can identify unilateral sensorineural hearing loss and unilateral conductive hearing loss in the middle ear.

Learn more about the Weber test here brainly.com/question/9064448

#SPJ4.

7 0
2 years ago
The answer is A and no matter how many times I tried I can't get it.
ryzh [129]
Imagine a skinny straw in the water, standing right over the hole. The WEIGHT of the water in that straw is the force on the tape. Now, the volume of water in the straw is (1 mm^2) times (20 cm). Once you have the volume, you can use the density and gravity to find the weight. And THAT's the force on the tape. If the tape can't hold that force, then it peels off and the water runs out through the hole. /// This is a pretty hard problem, because it involved mm^2, cm, and m^3. You have to be very very very careful with your units as you work through this one. If you've been struggling with it, I'm almost sure the problem is the units.
5 0
3 years ago
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