Answer:
water
Explanation:
coz out of the choices water is the only one that is not an element.
water formula is H2O
Answer:
It is not a property of light. It is your eyes and brain.
Specifically, the three kinds of cone cells in our eye that are sensitive to different ranges of the electromagnetic spectrum. The fact that there are three means that color is three dimensional, and is the reason the pure colors form a circle even though the spectrum of wavelengths is linear.
Visible light is part of the electromagnetic spectrum; light waves of different frequencies and wavelengths are distinguished as colors by the human eye. A prism can separate the colors of white light (dispersion) because different frequencies of light have different refractive indices for a given material.
Answer:
Option D (N/A-m)(m)(m/s)
Explanation:
(N/A-m)(m)(m/s) is the required dimensional analysis for calculation of emi
The average power produced by the soccer player is 710 Watts.
Given the data in the question;
- Mass of the soccer player;
- Energy used by the soccer player;
- Time;
Power; 
Power is simply the amount of energy converted or transferred per unit time. It is expressed as:
We substitute our given values into the equation
![Power = \frac{5100000J}{7200s}\\\\Power = 708.33J/s \\\\Power = 710J/s \ \ \ \ \ [ 2\ Significant\ Figures]\\\\Power = 710W](https://tex.z-dn.net/?f=Power%20%3D%20%5Cfrac%7B5100000J%7D%7B7200s%7D%5C%5C%5C%5CPower%20%3D%20708.33J%2Fs%20%5C%5C%5C%5CPower%20%3D%20710J%2Fs%20%5C%20%5C%20%5C%20%5C%20%5C%20%5B%202%5C%20Significant%5C%20Figures%5D%5C%5C%5C%5CPower%20%3D%20710W)
Therefore, the average power produced by the soccer player is 710 Watts.
Learn more: brainly.com/question/20953664
Answer:
D = 2.38 m
Explanation:
This exercise is a diffraction problem where we must be able to separate the license plate numbers, so we must use a criterion to know when two light sources are separated, let's use the Rayleigh criterion, according to this criterion two light sources are separated if The maximum diffraction of a point coincides with the first minimum of the second point, so we can use the diffraction equation for a slit
a sin θ = m λ
Where the first minimum occurs for m = 1, as in these experiments the angle is very small, we can approximate the sine to the angle
θ = λ / a
Also when we use a circular aperture instead of slits, we must use polar coordinates, which introduce a numerical constant
θ = 1.22 λ / D
Where D is the circular tightness
Let's apply this equation to our case
D = 1.22 λ / θ
To calculate the angles let's use trigonometry
tan θ = y / x
θ = tan⁻¹ y / x
θ = tan⁻¹ (4.30 10⁻² / 140 10³)
θ = tan⁻¹ (3.07 10⁻⁷)
θ = 3.07 10⁻⁷ rad
Let's calculate
D = 1.22 600 10⁻⁹ / 3.07 10⁻⁷
D = 2.38 m
