What force causes a rolling ball to slow down and stop

What is the acceleration of the the object during the first 4 seconds?

AVprozaik [17]

Answer:

Velocity (m/s) over time (s) graph

We could write out our average acceleration as:

a = Δv/ Δta=Δv/Δta, equals, Δ, v, slash, Δ, t

a = (15 m/s - 0 m/s) / 0.2 seconds

a = 15 m/s / 0.2 seconds

a = 75 m/s / second

Explanation:

What this formula is telling us is that if we know the acceleration of an object, and the ... we can plug in our acceleration of 12.5 m/s2 for a, and 4 seconds for t.

Velocity (m/s) over time (s) graph

We could write out our average acceleration as:

a = Δv/ Δta=Δv/Δta, equals, Δ, v, slash, Δ, t

a = (15 m/s - 0 m/s) / 0.2 seconds

a = 15 m/s / 0.2 seconds

a = 75 m/s / second

6 0

3 years ago

The first artificial satellite to orbit the Earth was Sputnik I, launched October 4, 1957. The mass of Sputnik I was 83.5 kg, an

9966 [12]

Answer:

$-4.941*10^8J.$

Explanation:

To solve this exercise it is necessary to take into account the concepts related to gravitational potential energy, as well as the concept of perigee and apogee of a celestial body.

By conservation of energy we know that,

$\Delta U = \Delta_{perogee}-\Delta_{Apogee}$

Where,

$U= \frac{-GmM_e}{r}$

Replacing

$\Delta U = \frac{-GmM_e}{r_p}- \frac{-GmM_e}{r_a}$

$\Delta U = GmM_e (\frac{1}{r_A}-\frac{1}{r_p})$

Our values are given by,

$m = 85.5Kg$

$M_e = 5.97*10^{24}Kg$

$r_A = 7330Km$

$r_p = 6610Km$

$G = 6.67*10^{-11}Nm^2/Kg^2$

Replacing at the equation,

$\Delta U = (6.67*10^{-11})(85.5)(5.97*10^{24}) (\frac{1}{7330}-\frac{1}{6610})$

$\Delta U = -4.941*10^8J$

Therefore the Energy necessary for Sputnik I as it moved from apogee to perigee was $-4.941*10^8J.$

4 0

3 years ago

a student solving for the acceleration of an object has applied appropriate physics principles and obtained the expression a

kozerog [31]

Given:

$Force, f = 12 \frac{kg-m}{sec^{2} }$

$Mass, m = 7 kg$

$Acceleration, a_{1} = 3\;\frac{m}{sec^{2} }$

$a = a_{1}+\frac{f}{m}$

$Substitute\;the\;values\;of\;f,\;m\;and\;a_{1}\;in\;the\;above\;equation,$

$a = 3+\frac{12}{7}$

$a = 3 + 1.714$

Therefore, the acceleration is,

$a = 4.714\;\frac{m}{sec^{2} }$

<h3>Explain Acceleration?</h3>

An object's rate of changing its velocity is known as its acceleration, which is a vector quantity. If an object's velocity is changing, it is accelerating. When anything moves faster or slower in a straight line, it is said to have been accelerated. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting.

To learn more about Acceleration, visit:

brainly.com/question/12550364

#SPJ4

3 0

1 year ago

If you were to apply a force of 15N to a medicine ball with a mass of 10kg, what would its acceleration be

tresset_1 [31]

One of the equations for force is: Force = mass × acceleration.

The force and mass are given and so:

F=15N

m=10kg

By plugging in these values we obtain:

$F=ma\\\\15=10(a)\\$

$\frac{15}{10}=\frac{10(a)}{10}\\\\a=\frac{15}{10}=1.5m/s^2$

So the acceleration is a=1.5m/s^2

6 0

3 years ago

sla’s change in velocity is 30 m/s, and Hazel has the same change in velocity. Which best explains why they would have different

sweet [91]

Because acceleration depends not only on the change in velocity.
It also depends on the time during which the change occurs.
The formula is

Acceleration = (change in velocity) divided by (time for the change) .

Maybe Sla changed his velocity in 3 seconds, but Hazel
took all morning to change hers. In that case, even though
the amounts of change were equal, the times were different,
so the quotients of (change/time) were different.

8 0

3 years ago