The position of a particle moving along the x axis is given in centimeters by x=9.75+1.50t³, where t is in seconds. Calculate(a)
the average velocity during the time interval t=2.00 s to t=3.00 s(b) the instantaneous velocity at t=2.00 s(c)the instantaneous velocity at t=3.00 s(d)the instantaneous velocity at t=2.50 s(e)the instantaneous velocity when the particle is midway between its positions at t=2.00 s and t=3.00 s.(f) graph it
1 answer:
You might be interested in
In this problem we have the electric field intensity E:
E = 6.5 × newtons/coulomb
We have the magnitude of the load:
q = 6.4 × coulombs
We also have the distance d that the load moved in a direction parallel to the field 1.2 × meters.
We know that the electric potential energy (PE) is:
PE = qEd
So:
PE = (6.4 × )(6.5 ×
)(1.2 ×
)
PE = 5.0 x joules
None of the options shown is correct.