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liq [111]
3 years ago
7

The position of a particle moving along the x axis is given in centimeters by x=9.75+1.50t³, where t is in seconds. Calculate(a)

the average velocity during the time interval t=2.00 s to t=3.00 s(b) the instantaneous velocity at t=2.00 s(c)the instantaneous velocity at t=3.00 s(d)the instantaneous velocity at t=2.50 s(e)the instantaneous velocity when the particle is midway between its positions at t=2.00 s and t=3.00 s.(f) graph it

Physics
1 answer:
OlgaM077 [116]3 years ago
8 0

Answer:

The solution and the graph are in the attached files below

Explanation:

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What is the downward pull on an object due to gravity?
Strike441 [17]

Answer:

force of gravity

Explanation:

The force of gravity is that which draws the bodies towards the surface of the Earth.

 The force of gravity brakes the objects that move up and accelerates those that move down. It causes a parabolic movement in what we throw upwards,

3 0
3 years ago
Read 2 more answers
g Two radiation modes (one at the center frequency lIo and the other at lIO+?lI) are excited with 1000 photons each. Determine t
Schach [20]

Answer:

a) P=0.25x10^-7

b) R=B*N2*E

c) N=1.33x10^9 photons

Explanation:

a) the spontaneous emission rate is equal to:

1/tsp=1/3 ms

the stimulated emission rate is equal to:

pst=(N*C*o(v))/V

where

o(v)=((λ^2*A)/(8*π*u^2))g(v)

g(v)=2/(π*deltav)

o(v)=(λ^2)/(4*π*tp*deltav)

Replacing values:

o(v)=0.7^2/(4*π*3*50)=8.3x10^-19 cm^2

the probability is equal to:

P=(1000*3x10^10*8.3x10^-19)/(100)=0.25x10^-7

b) the rate of decay is equal to:

R=B*N2*E, where B is the Einstein´s coefficient and E is the energy system

c) the number of photons is equal to:

N=(1/tsp)*(V/C*o)

Replacing:

N=100/(3*3x10^10*8.3x10^-19)

N=1.33x10^9 photons

7 0
3 years ago
You move a 2.5 kg book from a shelf that is 1.2 m above the ground to a shelf that is 2.6 m above the ground. What is the change
Sophie [7]
The change in potential energy of an object is given by
U=mg \Delta h
where
m is the mass of the object
g is the gravitational acceleration
\delta h is the increase in altitude of the object

In our problem, m=2.5 kg is the mass of the book, g=9.81 m/s^2 and 
\Delta h=2.6 m -1.2 m=1.4 m is the increase in altitude of the book, so its variation of potential energy is
U=mg\Delta h=(2.5 kg)(9.81 m/s^2)(1.4 m)=34.3 J
8 0
3 years ago
A particle's position is given by x = 4.0t2 - 32t + 36, with x in meters and time t in seconds. At what position does the partic
daser333 [38]
Firstly, we must find the equation the speed, it can be obtained by the derivative of x =<span>x = 4.0t2 - 32t + 36, it means v= 8.0t-32. the particule stops means v= 0, and 0= 8.0t-32, which implies 8t=32, so t=4s, and then x(t=4) = 4.0(4)^2 - 32(4) + 36= - 28m
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8 0
3 years ago
Federal board paper of class 10 of physics​
zzz [600]

Answer:

If you are looking for past papers you can search that up and you will find plenty of resources that will help you out.

8 0
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