The gravitational potential energy of the system will decreases from 1,250 J to 625 J. Option A is corect.
<h3>What is the law of conservation of energy?</h3>
According to the Law of Conservation of Energy, energy can neither be created nor destroyed, but it can be transferred from one form to another.
The total energy is the sum of all the energies present in the system. The potential energy in a system is due to its position in the system.
TE=KE+GPE
Case 1;
1450 = 200 J+GPE
GPE=1450 -200
GPE=1250 J
Case 2;
1450 = 825 J+GPE
GPE=1450 -825
GPE=625 J
The gravitational potential energy of the system will decreases from 1,250 J to 625 J.
Hence, option A is corect.
To learn more about the law of conservation of energy, refer to brainly.com/question/2137260.
#SPJ1
It depends whether or not the object in moving relative or not to the reference point, for instance imagine a void where there were no dimensions, but there was an object. You can’t tell if the object is moving or not without a reference point.
Feelings of jealousy and envy
Answer:
I = 1.06886 N s
Explanation:
The expression for momentum is
I = F t = Δp
therefore the momentum is a vector quantity, for which we define a reference system parallel to the floor
Let's find the components of the initial velocity
sin 28.2 = v_y / v
cos 28.2= vₓ / v
v_y = v sin 282
vₓ = v cos 28.2
v_y = 42.8 sin 28.2 = 20.225 m / s
vₓ = 42.8 cos 28.2 = 37.72 m / s
since the ball is heading to the ground, the vertical velocity is negative and the horizontal velocity is positive, it can also be calculated by making
θ = -28.2
v_y = -20.55 m / s
v_x = 37.72 m / s
X axis
Iₓ = Δpₓ = 
since the ball moves in the x-axis without changing the velocity, the change in moment must be zero
Δpₓ = m 
- m v₀ₓ = 0
v_{fx} = v₀ₓ
therefore
Iₓ = 0
Y axis
I_y = Δp_y = p_{fy} -p_{oy}
when the ball reaches the floor its vertical speed is downwards and when it leaves the floor its speed has the same modulus but the direction is upwards
v_{fy} = - v_{oy}
Δp_y = 2 m v_{oy}
Δp_y = 2 0.0260 (20.55)
= 1.0686 N s
the total impulse is
I = Iₓ i ^ + I_y j ^
I = 1.06886 j^ N s
To obtain the vertical component of the velocity, it is necessary to multiply the velocity at this time by sin 45 degrees. Since the velocity is not given, it must be solved first by dividing the distance by the time. To show this:
Velocity = distance / time
Velocity = 30 m / 4s
Velocity = 7.5 m/s
Vertical velocity = 7.5 sin 45
Vertical velocity = 5.3 m/s
