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Kruka [31]
3 years ago
15

Write the equation of the line, in slope-intercept form, with the

Mathematics
1 answer:
mash [69]3 years ago
6 0

Answer:

y= -5(x-4)

Step-by-step explanation:

any point slope equation is in form y-y1 = m(x-x1)

plug in the point and constant value

y-0 = -5(x-4)

y= -5(x-4)

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What is the antiderivative of secx-tanx
Ivenika [448]

Step-by-step explanation:

∫ (sec x − tan x) dx

∫ sec x dx + ∫ -tan x dx

∫ (sec²x + sec x tan x) / (sec x + tan x) dx + ∫ (-sin x / cos x) dx

ln(sec x + tan x) + ln(cos x) + C

6 0
3 years ago
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Solve the given system of equations using either Gaussian or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTI
cricket20 [7]

Answer:

The system has infinitely many solutions

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

Step-by-step explanation:

Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.

An Augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

There are three elementary matrix row operations:

  1. Switch any two rows
  2. Multiply a row by a nonzero constant
  3. Add one row to another

To solve the following system

\begin{array}{ccccc}x_1&-3x_2&-2x_3&=&0\\-x_1&2x_2&x_3&=&0\\2x_1&+3x_2&+5x_3&=&0\end{array}

Step 1: Transform the augmented matrix to the reduced row echelon form

\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]

This matrix can be transformed by a sequence of elementary row operations

Row Operation 1: add 1 times the 1st row to the 2nd row

Row Operation 2: add -2 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1

Row Operation 4: add -9 times the 2nd row to the 3rd row

Row Operation 5: add 3 times the 2nd row to the 1st row

to the matrix

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

The reduced row echelon form of the augmented matrix is

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

which corresponds to the system

\begin{array}{ccccc}x_1&&-x_3&=&0\\&x_2&+x_3&=&0\\&&0&=&0\end{array}

The system has infinitely many solutions.

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

7 0
3 years ago
17.25 round up to ones
Irina18 [472]
17.24

Since 7 comes after 5 we need to round to the next number.....18.00

17.24 rounded to ones = 18.00

Hope I helped:P

7 0
3 years ago
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Express the interval shown on the number line in inequality notation.
Bess [88]

Answer: x < -3 or x > 5

Step-by-step explanation: Interval notation shows the values of x. X is less than -3, or greater than 5.

6 0
3 years ago
Is this expression equivalent?<br> 3v+v and 12v over 3
xeze [42]
Yes this is equal because 3v+v is 4v and if you divide 12v by 3 you also get 4v
7 0
3 years ago
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