Ask question

Ask question

All categories

3 years ago

11

What is the answer with this math

2 answers:

xenn [34]3 years ago

3 0

Find the least common denominator of 2 and 3, which is 6. Because you had to multiply 2 by 3 to get 6, you have to multiply 1 by 3, you then get 3/6. Because you had to multiply 3 by 2 to get 6, you have to multiply 1 by 2, you then get 2/6. Now, you can subtract 3/6 - 2/6, which equals 1/6. Hope this helps!

sergiy2304 [10]3 years ago

3 0

The Answer Should Be 1/6

You might be interested in

lutik1710 [3]

Answer:

$\huge \boxed{\mathrm{804}}$

Step-by-step explanation:

$\sf The \ initial \ population \ of \ the \ town \ was \ 568.$

$\sf 236 \ migrated \ to \ the \ town.$

$568+236$

$=804$

$\sf The \ present \ population \ of \ the \ town \ is \ 804.$

5 0

3 years ago

Read 2 more answers

Lim x-1 x2 - 1/ sin(x-2)

balu736 [363]

Answer:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=0$

Explanation:

Assuming the correct expression is to find the following limit:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}$

Use the property the limit of the quotient is the quotient of the limits:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}$

Evaluate the numerator:

$\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}=\frac{1^2-1}{\lim_{x \to1}sin(x-2)}=\frac{0}{\lim_{x \to 1}sin(x-2}$

Evaluate the denominator:

Since $\lim_{x \to1}sin(x-2)\neq 0$

$\frac{0}{\lim_{x \to1}sin(x-2)}=0$

4 0

3 years ago

What is the mad of 7, 9, 6, and 6

Alborosie

The <span>Mean Absolute Deviation of 7,9,6,6 is 1 hope it helps <3</span>

3 0

3 years ago

1. What are two other ways you could rewrite 50%?

NNADVOKAT [17]

0.5 is the first way

1/2 is the second way

50% is the third way.

Hope that helps bud :).

8 0

2 years ago

SOMONE PLS HURRY AND ANSWER I IWLL GIVE BRAINLIEST PLEASEEE

Ierofanga [76]

The answers are in the photo!

4 0

3 years ago

Read 2 more answers