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garik1379 [7]
3 years ago
8

Trish opens a savings account with $1,000. The account does not earn interest. She withdraws $100 each month. The bank created a

graph
for Trish that shows the amount of money, y, in the account after x months.
What does the x-intercept on the graph represent?
O A. The amount she withdraws every month.
B. The amount in the account after x years.
O
c. The amount in the account when it was opened.
O
D. The number of years the account has been open.
O
E. The number of months until the account has a balance of 0.
Mathematics
1 answer:
Veronika [31]3 years ago
7 0
The answer would be D
Because x on the graph represents time
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The two cars will be 5.5 miles apart after 5.5 hours.

Step-by-step explanation:

Given,

Speed of first car = 57 mph

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Distance covered by first car = Speed * Time

Distance covered by first car = 57*5.5 = 313.5 miles

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Distance covered by other car = 58*5.5 = 319 miles

Difference = 319 - 313.5

Difference = 5.5 miles

The two cars will be 5.5 miles apart after 5.5 hours.

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Consider a fictitious company, Teslala, that produces a single type of electronic vehicle, Model Z. The demand for Model Z depen
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The ratio X/Y for the fictitious company, Teslala, that produces a single type of electronic vehicle, Model Z is 10/pY.

<h3>What is a mathematical model?</h3>

A mathematical model is the model which is used to explain the any system, the effect of the components by study and estimate the functions of systems.

Consider a fictitious company, Teslala, that produces a single type of electronic vehicle, Model Z.

The demand for Model Z depends on the gasoline price (q) because customers tend to purchase an electronic vehicle as a substitute for vehicles that run on gasoline when the gasoline price increases.

The demand for Model Z is estimated as

D(p) = 180 + 10q - 4p

Here, <em>p</em> is the price of Model Z.

Consider the following two statements:

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D(p) = 180 + 10q - 4p\\D(p) = 180 + 10(q+1) - 4(p+X)

  • 2. When the average gasoline price q increases by $1, the demand at the revenue-maximizing price (i.e., D(p*)) increases by a factor of Y.

D(p)+Y = 180 + 10q - 4p\\(D(p)+Y) = 180 + 10(q+1) - 4(p+X)\\Y= 180 + 10(q+1) - 4(p+X)-D(p)\\

Put the value of demand at the revenue-maximizing price as,

Y= 180 + 10(q+1) - 4(p+X)-(180 + 10q - 4p)\\Y= 180 + 10q+10 - 4p-pX-180 - 10q + 4p\\Y= 10 -pX\\1=\dfrac{10}{Y}-\dfrac{pX}{Y}\\\dfrac{10}{Y}=\dfrac{pX}{Y}\\\dfrac{10}{pY}=\dfrac{X}{Y}

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Convert 1 = 4 to polar form.
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Step-by-step explanation: i think this may help you

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Answer:

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Step-by-step explanation:

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