Answer:
a
![H =212.6 \ J](https://tex.z-dn.net/?f=H%20%20%3D212.6%20%5C%20%20J)
b
![v = 7.647 \ m/s](https://tex.z-dn.net/?f=v%20%20%3D%20%207.647%20%20%5C%20%20m%2Fs)
Explanation:
From the question we are told that
The child's weight is ![W_c = 287 \ N](https://tex.z-dn.net/?f=W_c%20%20%3D%20%20287%20%5C%20N)
The length of the sliding surface of the playground is ![L = 7.20 \ m](https://tex.z-dn.net/?f=L%20%3D%20%207.20%20%5C%20%20m)
The coefficient of friction is ![\mu = 0.120](https://tex.z-dn.net/?f=%5Cmu%20%3D%20%200.120)
The angle is ![\theta = 31.0 ^o](https://tex.z-dn.net/?f=%5Ctheta%20%3D%2031.0%20%5Eo)
The initial speed is ![u = 0.559 \ m/s](https://tex.z-dn.net/?f=u%20%3D%20%200.559%20%5C%20%20m%2Fs)
Generally the normal force acting on the child is mathematically represented as
=> ![N = mg * cos \theta](https://tex.z-dn.net/?f=N%20%20%3D%20%20mg%20%20%2A%20%20cos%20%5Ctheta)
Note ![m * g = W_c](https://tex.z-dn.net/?f=m%20%2A%20%20g%20%20%3D%20%20W_c)
Generally the frictional force between the slide and the child is
![F_f = \mu * mg * cos \theta](https://tex.z-dn.net/?f=F_f%20%20%3D%20%20%5Cmu%20%2A%20%20mg%20%20%2A%20%20cos%20%5Ctheta)
Generally the resultant force acting on the child due to her weight and the frictional force is mathematically represented as
![F =m* g sin(\theta) - F_f](https://tex.z-dn.net/?f=F%20%3Dm%2A%20g%20sin%28%5Ctheta%29%20-%20F_f)
Here F is the resultant force and it is represented as ![F = ma](https://tex.z-dn.net/?f=F%20%3D%20%20ma)
=> ![ma = m* g sin(31.0) - \mu * mg * cos (31.0)](https://tex.z-dn.net/?f=ma%20%3D%20%20%20m%2A%20g%20sin%2831.0%29%20%20-%20%5Cmu%20%2A%20%20mg%20%20%2A%20%20cos%20%2831.0%29)
=> ![a = g sin(31.0)- \mu * g * cos (31.0)](https://tex.z-dn.net/?f=a%20%3D%20%20g%20sin%2831.0%29-%20%20%5Cmu%20%2A%20%20g%20%20%2A%20%20cos%20%2831.0%29)
=> ![a = 9.8 * sin(31.0) - 0.120 * 9.8 * cos (31.0)](https://tex.z-dn.net/?f=a%20%3D%20%20%20%209.8%20%2A%20%20sin%2831.0%29%20-%200.120%20%2A%20%209.8%20%20%2A%20%20cos%20%2831.0%29)
=>![a = 4.039 \ m/s^2](https://tex.z-dn.net/?f=a%20%3D%20%204.039%20%5C%20m%2Fs%5E2)
So
![F_f = 0.120 * 287 * cos (31.0)](https://tex.z-dn.net/?f=F_f%20%20%3D%20%200.120%20%20%2A%20287%20%20%2A%20%20cos%20%2831.0%29)
=> ![F_f = 29.52 \ N](https://tex.z-dn.net/?f=F_f%20%20%3D%2029.52%20%5C%20%20N)
Generally the heat energy generated by the frictional force which equivalent tot the workdone by the frictional force is mathematically represented as
![H = F_f * L](https://tex.z-dn.net/?f=H%20%20%3D%20%20F_f%20%20%2A%20L)
=> ![H = 29.52 * 7.2](https://tex.z-dn.net/?f=H%20%20%3D%2029.52%20%2A%20%207.2)
=> ![H =212.6 \ J](https://tex.z-dn.net/?f=H%20%20%3D212.6%20%5C%20%20J)
Generally from kinematic equation we have that
![v^2 = u^2 + 2as](https://tex.z-dn.net/?f=v%5E2%20%20%3D%20%20u%5E2%20%20%2B%20%202as)
=> ![v^2 = 0.559^2 + 2 * 4.039 * 7.2](https://tex.z-dn.net/?f=v%5E2%20%20%3D%20%200.559%5E2%20%20%2B%20%202%20%2A%204.039%20%2A%207.2)
=> ![v = \sqrt{0.559^2 + 2 * 4.039 * 7.2}](https://tex.z-dn.net/?f=v%20%20%3D%20%20%5Csqrt%7B0.559%5E2%20%20%2B%20%202%20%2A%204.039%20%2A%207.2%7D)
=> ![v = 7.647 \ m/s](https://tex.z-dn.net/?f=v%20%20%3D%20%207.647%20%20%5C%20%20m%2Fs)
Answer:0.00125 watts
Explanation:
resistance=50 ohms
Current=5 milliamps
Current=5/1000 milliamps
Current =0.005 amps
power=(current)^2 x (resistance)
Power=(0.005)^2 x 50
Power=0.005 x 0.005 x 50
Power=0.00125 watts
Answer:
M1 V1 = M1 V2 + M2 V3 conservation of momentum
V2 = (M1 V1 - M2 V3) / M1 where V2 = speed of M1 after impact
V2 = (3 * 9 - 1.5 * 5) / 9 = (27 - 7.5) / 9 = 2.17 m/s
Note: All speeds are in the same direction and have the same sign
I believe it’s B but i’m not sure
Answer:
For real gas the volume of a given mass of gas will increase with increase in temperature.
Explanation:
With the piston head locked in place and place above the fire,the volume of the gas will increase,because the volume of a given mass of gas increases with increase temperature.