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1 year ago

A race horse can run a mile race in just under 2 minutes. Is it possible for

Physics

1 answer:

liubo4ka [24]1 year ago

7 0

Answer:

Yes.

Explanation:

A kilometer is less than a mile, therefore if a horse can finish one mile in less than 2 minutes then it can certainly do a kilometer in less than two minutes.

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1. KCIO3 -> KCI - O2. Reaction Type

nalin [4]

Answer:

thermal decomposition reaction

Explanation:

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3 years ago

A 2kg picture frame sits on a shelf at a height of 0.5 m

mote1985 [20]

Can u please complete the question and make it clear

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3 years ago

Part a of the drawing shows a bucket of water suspended from the pulley of a well; the tension in the rope is 90.5 n. part b sho

Butoxors [25]

Missing figure in the problem: https://www.physicsforums.com/attachments/p4-46-gif.117834/

Solution:

part a) The bucket is not moving so the resultant of the forces acting on it is zero. Let's apply the equation of equilibrium. We have:
$mg-2T=0$
so
$mg=2T$
where T=90.5 N is the tension of the rope, and a factor 2 is applied because the string holds the bucket twice. From this we find
$mg=2\cdot 90.5 N= 181 N$

part b) Here the situation is different: the string holds the bucket only in one point. Moreover, the bucket is pulled up at constant velocity, so zero acceleration: this means that the resultant of the forces acting on the bucket is zero. Therefore, the equation of equilibrium in this case is
$mg-T=0$
and so, since we know from part a) that $mg=181 N$ , we can find the new tension T:
$T=mg=181 N$

3 0

3 years ago

What variables affect gravity

vlabodo [156]

Gravity is affected by the size of an object and the distance between the objects. When the mass of an object increases the force of gravity increases as well.

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3 years ago

The blade of a windshield wiper moves through an angle of 90.0° in 0.397 s. The tip of the blade moves on the arc of a circle th

Arlecino [84]

Answer:

$a=5.88\ m/s^2$

Explanation:

Given that,

The blade of a windshield wiper moves through an angle of 90.0° in 0.397 s

The radius of the circlular path is 0.376 m

We need to find the magnitude of the centripetal acceleration of the tip of the blade. Let it is a. The formula of the centripetal acceleration is given by :

$a=\dfrac{v^2}{r}$

v is velocity, $v=\dfrac{2\pi r}{t\\}$

It moves through an angle of 90 degrees, it means $v=\dfrac{\dfrac{1}{4}\times 2\pi r}{t\\}$

So,

$a=\dfrac{(\dfrac{\dfrac{1}{4}\times 2\pi r}{t\\})^2}{r}\\\\=\dfrac{\pi^2 r}{4t^2}\\\\=\dfrac{\pi^2 \times 0.376}{4(0.397 )^2}\\\\=5.88\ m/s^2$

So, the magnitude of the centripetal acceleration of the tip of the blade is $5.88\ m/s^2$ .

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3 years ago